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3 years ago

Idk ;-; lol help meeeee

Mathematics

1 answer:

masha68 [24]3 years ago

8 0

Step-by-step explanation:

the answer is $.75

:))))))

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The answer is 21.
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3 years ago

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Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

Final answer:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

3 years ago

A) 5y +32=72 B) K/2+24=29

iren [92.7K]

Step-by-step explanation:

A)y=8

B)k=10

5y=72-32

5y=40

y=8

1/2k+24=29

k+48=58

k=58-48

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

I used the graph shown below.

Step-by-step explanation:

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