The answer is 18
I hope this helps
A biased example: Asking students who are in line to buy lunch
An unbiased example: Asking students who are leaving/going to lunch(<em>NOT buying </em><em>lunch</em><em />).
But in this case, the answer choices can be... confusing.
Don't panic! You're given numbers and, of course, your use of logic.
Answer choice A: 100 students grades 6-8
Answer choice B: 20-30 students any <em>one</em> grade<em></em><em>
</em>Answer choice C: 5 students
<em></em>Answer choice D: 50 students grade 8
An unbiased example would be to choose students from <em>any grade.</em> So we can eliminate choices B and D.
Now, the question wants to <em>estimate how many people at your middle school buy lunch.</em> This includes the whole entire school, and if you are going to be asking people, you aren't just going to assume that if 5 people out of 5 people you asked bought lunch, the whole school buys lunch.
So, to eliminate all bias and/or error by prediction, answer choice A, the most number of students, is your answer.
1- Leave the 1st case empty
2- Write on the 1st row each element of the trinomial in each case
3-Write on the 1st column in each case each of the element of the binomial
║ y² -3y 9
----------- ║-----------------------------------------------------
y ║ y³ -3y² 9y
----------- ║---------------------------------------------------
3 ║ 3y² -9y 27
------------║----------------------------------------------------
TOTAL║(y³+3y²) +(-3y²-9y) + ( 9y+27)
If you add the Total you will get: (A) Y³+27
The denominator can be 3 if the numerator is 1
Answer:
x-3y-z
Step-by-step explanation:
separate common terms and add them
1/2x+3/4x=1x
-2y-y=-3y
2z-3z=-1z
1x-3y-1z
