2 years ago

After a dilation centered at the origin, the image of CD is C'D'.

Mathematics

1 answer:

RSB [31]2 years ago

5 0

Answer: 3/2

Step-by-step explanation: just believe me

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Evaluate x(y+3)/(3+y)z for x=12, y=1, and z=6. A) 2 B) 5 C) 8 D) 6

fgiga [73]

Answer:

Step-by-step explanation:

We take the equation

$x(y+3)/(3+y)z$

and substitute the values for each individual variable in the problem. It looks like this:

$12(1+3)/(3+1)6$

Now we can solve the equation.

When solved, it equals 2.

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3 years ago

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Write the slope-intercept form of the equation of each line. identify the slopes y-intercept.

iren [92.7K]

Answer:

1. 3,0,y=3x

2. -3/5, 1, y=-3/5x+1

3. -2/3, -4,y=-2/3x-4

4. 0, 4, y=4

5. 1, 5, y=x+5

6. 2, 0, y=2x

7. 4, 5, y=4x+5

8. 3/2, 4, y=3/2x+4

hopefully this helps :)

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2 years ago

(03.01) The domain of the following relation R {(3,-2), (1, 2), (-1,-4), (-1, 2)} is

Anna35 [415]

The domain is set of x-value.

Therefore, the domain of the relation Domain of R = {3,1,-1}

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2 years ago

The parent function f(x)=log^3x has been transformed by reflecting it over the X axis, stretching it vertically by a factor of t

NARA [144]

Answer:

Step-by-step explanation:

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3 years ago

If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta

iren [92.7K]

$\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}$

$\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}$

$\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}} =- \frac{3}{4}$

5 0

3 years ago