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Licemer1 [7]
3 years ago
9

given triangle GHI with G(4,-3), H(-4,2) and I(2,4), find the perpendicular bisector of HI in standard form.

Mathematics
2 answers:
nekit [7.7K]3 years ago
8 0
The perpendicular bisector would be the line that connects with the line HI at a 90 degree angle and in the mid-point. This means that we would have to find the slope of the line HI and take the opposite. The slope of HI is 1/3. This means that the slope of the perpendicular line is -3. Now we must solve for the line that crosses through the midpoint. y=mx+b we know that m=-3 and that the midpoint is at -1,3 so x=-1 and y=3.  3=(-3)-1+b. We then solve for b and find it to be 0.  So the final answer is y= -3x
aev [14]3 years ago
3 0

Answer: The final answer is y=-3x


Step-by-step explanation:


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Answer:

A  3^4 * 3^-4 / 3^6

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Step-by-step explanation:

( 3^2 * 3^-2)

-------------------  all the the power of 2

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First simplify the numerator

We know a^b* a^c = a^(b*c)

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-------------------  all to the power of 2

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( 3^(0))

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-------------------  all to the power of 2

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We know a^b/ a^c = a^(b-c)

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3^(-3*2)

3^ -6

We know the negative exponent takes if from the numerator to the denominator

1 / 3^6

The other correct choice is A

3^4 * 3^-4 = 3^0 which is 1

1/3^6 is the same answer

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