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2 years ago

given triangle GHI with G(4,-3), H(-4,2) and I(2,4), find the perpendicular bisector of HI in standard form.

2 answers:

8 0

The perpendicular bisector would be the line that connects with the line HI at a 90 degree angle and in the mid-point. This means that we would have to find the slope of the line HI and take the opposite. The slope of HI is 1/3. This means that the slope of the perpendicular line is -3. Now we must solve for the line that crosses through the midpoint. y=mx+b we know that m=-3 and that the midpoint is at -1,3 so x=-1 and y=3. 3=(-3)-1+b. We then solve for b and find it to be 0. So the final answer is y= -3x

aev [14]2 years ago

3 0

Answer: The final answer is y=-3x

Step-by-step explanation:

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Pls PLS solve T_T i tried everything

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12√3 is the correct answer

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The answer is 5,180! I used a calculator

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√7.5×√3.5 step and answer

irina1246 [14]

Answer:

√105/2

Step-by-step explanation:

Given the surd expression √7.5×√3.5, this can also be expressed as;

√7.5×√3.5

= √75/10 × √35/10

= √(75×35)/10×`10

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3 years ago

State whether the value for the unknown makes inequalities <br><br> 74/e < 12

Nezavi [6.7K]

Answer:

Yes

Step-by-step explanation:

74/e < 12

Since e is in the denominator, e can not be 0.

If e > 0,

74/e < 12

74 < 12e

e > 74/12

e < 37/6

If e < 0,

(When you multiply by e, which is a negative value, inequality reverses)

74 > 12e

e < 74/12

e < 37/6

6 0

2 years ago

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A couple plans to have children until they get a girl, but they agree they will not have more than three children, even if all

barxatty [35]

Answer:

a)Let X be number of children

X=1,2,3

P(X=1)= 0.47

P(X=2) = 0.2491

P(X=3) = 0.942923

b) 3.7970

c) 1.6232

Step-by-step explanation:

The complete question is:

A couple plans to have children until they get a girl, but they agree they will not have more than three children, even if all are boys. Assume that the probability of having a girl is 47.00%.

a) Create a probability model for the number of children they'll have.

X=1,2,3

P(X=1)=??

P(X=2)= ??

P(X=30=???

(Round to four decimal places as needed

b) Find the expected number of children.

E(X)= ???

c) Find the expected number of boys they'll have.

Expected number of boys= ???

Solution:

Probability of a girl= 0.47

Probability of a boy= 0.53

a) P(X=1)= 0.47

P(X=2) = 0.47× 0.53= 0.2491

P(X=3)= 0.47× 0.53× 0.53 + 0.53× 0.53× 0.53

= 0.942923

b) E(number of children)= 1× P(X=1) + 2 ×P(X=2) + 3 × (PX=3)

= 3.796969

c) Y: number of boys

P(Y=1)= 0.53×0.47= 0.2491

P(Y=2) = 0.53×0.53×0.47=0.46375

P(Y=3)= 0.53× 0.53× 0.53= 0.148875

E(Y)= P(Y=1)×1 + P(Y=2)×2 + P(Y=3)×3

= 0.148875×3 +0.46375×2+0.2491 ×1

= 1.6232

5 0

2 years ago