HURRY FAST

Decorations for a seventh-grade dance take 1/6 of the student council's budget. entertainment takes 3/8 of the budget. what frac

defon

Answer:

11/24 is left over

Step-by-step explanation:

1/6 + 3/8 = 13/24

24/24 - 13/24 = 11/24

11/24 of the budget is left over

Hope this helps

5 0

3 years ago

Read 2 more answers

What is 0.05 repeating as a fraction ?

grin007 [14]

This is the best I got Require to make 2 equations with the same repeating part and subtract them to eliminate the repeating part.

begin by letting x = 0.5555555................. (1)

To obtain the same repeating part after the decimal point need to multiply by 10

hence 10x = 5.555555........................(2)

It is important to obtain 2 equations in x, where the recurring part after the decimal points are exactly the same.

now subtract (1) from (2) to obtain fraction

(2) - (1) : 9x=5⇒x=59

8 0

3 years ago

Ron has $49.Matt has $19 more than Ron.Naomi has $12 less than Matt.How much money do they have altogether?

EleoNora [17]

The answer to your question is,

They have a total of $173 altogether!

-Mabel <3

5 0

3 years ago

Read 2 more answers

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

What is the next term of the geometric sequence? 40/27, 20/9, 10/3, ??

kodGreya [7K]

Answer:

3/1

Step-by-step explanation:

8 0

3 years ago