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gavmur [86]
2 years ago
7

Please I need help !!! find the value of 5 if 5=1/4 (a+5) when a= -4​

Mathematics
2 answers:
Ray Of Light [21]2 years ago
7 0
The value is of this equation is -3.75
Nadya [2.5K]2 years ago
4 0

Hey there!

5 = 1/4(a + 5)

1/4(a + 5) = 5


1/4(-4 + 5) = 5

1/4(-4) + 1/4(5) = 5


1/4(-4) + 1/4(5)
= -1 + 5/4

= -1/1 + 5/4

= 1/4


1/4 ≠ 5
0.25 ≠ 5


Thus, your answer should most likely be: [FALSE] because the numbers are NOT equivalent to each other.

“a” should equal to “15”

Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

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Steps to solve:

x - 12 = 40

~Ad 12 to both sides

x = 52

Best of Luck!

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weqwewe [10]
<h3>Answer:  282.6 square units</h3>

====================================================

Work Shown:

r = 3 is the radius of the circular base

h = 12 is the height of the cylinder

pi = 3.14 approximately

SA = surface area of the cylinder

SA = 2pi*r^2 + 2pi*r*h

SA = 2*3.14*3^2 + 2*3.14*3*12

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3 0
3 years ago
The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
Rzqust [24]

The first term of the arithmetic progression exists at 10 and the common difference is 2.

<h3>How to estimate the common difference of an arithmetic progression?</h3>

let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.

We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula

The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.

9th term = 50

a + 8d = 50 ...............(1)

12th term = 65

a + 11d = 65 ...............(2)

subtract them, (2) - (1), we get

3d = 15

d = 5

If a + 8d = 50 then substitute the value of d = 5, we get

a + 8 * 5 = 50

a + 40 = 50

a = 50 - 40

a = 10.

Therefore, the first term is 10 and the common difference is 2.

To learn more about common differences refer to:

brainly.com/question/1486233

#SPJ4

4 0
2 years ago
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