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Anton [14]
3 years ago
8

Suppose 70% of all companies are classified as small companies and the rest as large companies. Suppose further, 82% of large co

mpanies provide training to employees, but only 18% of small companies provide training. A company is randomly selected without knowing if it is a large or small company; however, it is determined that the company provides training to employees.
What are the prior probabilities that the company is a large company or a small company? (Round the answers to 2 decimal place.)
p(small) =
p(large) =
What are the revised probabilities that the company is large or small? (Round your answers to 4 decimal places.) p(small) =
p(large) =
Based on your analysis, what is the overall percentage of companies that offer training? (Round your answer to 1 decimal place.)
Percentage = %
Business
1 answer:
aleksandrvk [35]3 years ago
3 0

Answer:

a) p(small) = 0.126

 p(large) = 0.246

b) p(small) = 0.6613

 p(large) =  0.3387

c) 37.2%

Explanation:

<u>A) determine that the company picked is a large company or small company</u>

<u>condition : the company provides training to its employees</u>

Given data:

p( small ) = 0.7,  p( large ) = 0.3,  p( training ∩ small ) = 0.18,  p( training ∩ large ) = 0.82 ,  p( No-training ∩ small ) = 0.82 ,  p( no-training ∩ large ) = 0.18

<em>A) </em><em>hence the probability of picking a small company that provides training </em>

P( small | training ) =  P(Training ∩ Small)* P(Small) = 0.18 * 0.7 = 0.126

<em>Probability of picking a large company that provides training </em>

P( large | training ) = P(training ∩ Large) *P(Large) = 0.82 * 0.3 = 0.246

<u>B) Determine the revised probabilities that company picked is large or small </u>

Revised probability  for a large company; P( large | training  )

P(Large | training) = P(Large ∩ training) / P(training)

                              = 0.246 / ( 0.126 + 0.246 ) = 0.6613

P( small | training ) = P( small ∩ training ) / P(training )

                               = 0.126 / ( 0.126 + 0.246 ) = 0.3387

<u>C) Overall percentage of companies that offer training </u>

p( training ) = 0.126 + 0.246  = 0.372 = 37.2%

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