4 because 8 x 3= 23 but 8 x 4= 32 so thre will be some left over.
Answer:
D. 3
Step-by-step explanation:
For g(x) = |x|, we seem to have ...
f(x) = 3|x| = 3g(x) = a·g(x)
The value of 'a' is 3.
She read nine chapters each hour
The domain of the function is possible values of independant varaible such that function is defined or have real values.
So the expression

is not defined for x = -6 and for x = 1, as expression becomes undefined for this values of x (Denominator becomes 0).
So answer is,

Option B is correct.