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Marina CMI [18]
3 years ago
6

Solve for x: 3x + 2x + 7 = 32

Mathematics
2 answers:
Leni [432]3 years ago
6 0

Answer:

The answer is x = 5

Step-by-step explanation:

I added similar elements, then I subtracted 7 from both sides, next I divided by 5 both sides, and lastly I got x = 5 as my answer.

yKpoI14uk [10]3 years ago
4 0
3x + 2x = 5x
5x + 7 = 32
5x = 32 - 7
5x = 25
5:5 ~ 25:5 = x = 5
The answer is x = 5
I hope this helps!
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**HELP!**
mr_godi [17]
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3 years ago
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Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!
forsale [732]

1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}

Step-by-step explanation:

The given equation is 4x^{2}-8x-1

Let a be the coefficient of x^{2}

Let b be the coefficient of x

Let c be the constant.

Then the roots α,β for the equation ax^{2}+bx+c are \dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}

So,α=\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}

β=\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}.

So the roots are 1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}

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3 years ago
CORRECT ANSWER GETS BRAINLIEST
borishaifa [10]
6 (-9)-3/2=14
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