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4 years ago

Please Help I'm in need for help

Mathematics

1 answer:

Mama L [17]4 years ago

5 0

I hope this helps you

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Find 63% of 77. a. 0.485 b. 48.5 c.0.818 d.81.8

8_murik_8 [283]

Answer:

b) 48.5

Step-by-step explanation:

63%= 0.63*77= 48.5

8 0

3 years ago

E^ln 1 =

tigry1 [53]

$a^{log_a(b)}=b$
$ln=log_e$
so
$e^{ln(x)}=e^{log_e(x)}=x$ for all x

first one
$e^{ln(1)}=1$
C is answer

2nd one
$e^{ln(5x)}=5x$
D is answer

5 0

4 years ago

Read 2 more answers

Solve the inequality. |4x + 2| < 26

balu736 [363]

Hello,
Answer D

1) if 4x+2>0 then |4x+2|=4x+2
==> 4x+2<26
==>4x<24
==>x<6

2) if 4x+2<0 then |4x+2|=-(4x+2)=-4x-2

==>-4x-2<26
==>-4x<28
==>x>-7

thus -7<x<6

8 0

3 years ago

Write in simplest form:<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti

Charra [1.4K]

Answer:

$2a^3b^2\sqrt[3]{3a}$

Step-by-step explanation:

Use the following rules for exponents:

$a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x$

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

$8*3=24\\\\2^3=8$

Insert:

$\sqrt[3]{2^3*3a^{10}b^6}$

Now split the exponents. Split 10 into as many 3's as possible:

$10=3+3+3+1$

Insert as exponents:

$\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}$

Split 6 into as many 3's as possible:

$6=3+3$

Insert as exponents:

$\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}$

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

$2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}$

Simplify:

$2a^3b^2\sqrt[3]{3a}$

:Done

6 0

3 years ago

How do you write 20% as a decimal

77julia77 [94]

Answer:

0.2

Step-by-step explanation:

20/100=0.2

3 0

3 years ago

Read 2 more answers