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dusya [7]
3 years ago
10

The local muffler replacement shop charges $75 for parts and $25 per hour for labor. Write a expresstion with parentheses to des

cribe the cost, in dollars, of a replacement if the job takes 4 hours.​
Mathematics
1 answer:
ziro4ka [17]3 years ago
6 0

Answer:

Step-by-step explanation:

75+ 25x

75+25(4)

75+100

175

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The cost of 17 m cloth is $77 5/7<br> find its cost per meter.
lukranit [14]

Answer:

Step-by-step explanation:

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HELP ME ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.
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Step-by-step explanation:

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5 0
3 years ago
A high school drama club is putting on their annual theater production. There is a maximum of 800 tickets for the show. The cost
astra-53 [7]
<span>a.) Let x be the number of tickets sold before the event and y the number of tickets sold on the day of the event. Then x + y =< 800 and 6x + 9y >= 5000. (b.) Suppose the club sold 440 tickets before the event, i.e. x = 440, maximum number of tickets remaining to be sold = 800 - 440 = 360. Maximum amount realized from the sales supposing all tickets were sold = 6(440) + 9(360) = 2640 + 3240 = $5880 which is greater than $5000. Therefore, it is possible for the club to sell enough additional tickets on the day of the show to meet the expenses of the show.</span>
3 0
3 years ago
Prove that if m, d, and k are integers and d &gt; 0, then (m + dk) mod d = m mod<br> d.
masya89 [10]
From the rules of modular arithmetic, (A+B)mod C= (A)modC +(B)modC

So,  (m + dk) mod d =  (m) mod d+<span> (dk) mod d

clearly </span>(dk) mod d = 0, as one of the things (dk) mod d represents, is the remainder of dk, when divided by d, which is clearly 0.


Thus

(m + dk) mod d =  (m) mod d+ (dk) mod d= (m) mod d+ 0=(m) mod d


(m + dk) mod d =(m) mod d
6 0
3 years ago
A radio antenna is kept perpendicular to the ground by three wires of equal length. The wires touch the ground at three points o
Elena-2011 [213]

Answer:

The coordinates of the base of the antenna is (-6. 1)

Step-by-step explanation:

Here  we are required to find the center of a circle given points on the circumference

The equation of  a circle is

(x - h)² + (y - k)² = r²

Where:

x and y are points on the circumference

h and k are coordinates of the center of the circle and

r = The radius of the circle

Since we have the values for the points on the circumference, we are left with three unknowns, which we can find with three equations as follows;

By plugging in the values for x and y at the respective points we get,

At (9, -19) → (9 - h)² + (-19 - k)² = r²...............(1)

At (-21, -19) → (-21 - h)² + (-19 - k)² = r².....,...(2)

At (14, 16 ) → (14 - h)² + (16 - k)² = r² ............(3)

Solving, we get  from (1)  (-19 - k)² = r² - (9 - h)²

Plugging in the value of (-19 - k)² in equation (2) we get

(-21 - h)² + r² - (9 - h)² = r²

So that (-21 - h)²  - (9 - h)² = r² -  r² = 0

and   (-21 - h)²  - (9 - h)² = 0 gives

60·h +360 = 0 or h = -6

Plugging in the value of h = -6 in equation (3) we get

(14 - (-6))² + (16 - k)² = r²

20² + (16 - k)² = r² .................(4)

similarly from equation (1) we get

(9 - (-6))² + (-19 - k)² = r²

15² + (-19 - k)² = r²  ................(5)

Subtracting equation (5) from (4) gives

20² - 15² +  (16 - k)² - (-19 - k)² = 0

Which gives

-70·k + 70 = 0

or k = 1

Therefore the coordinates of the base of the antenna = (-6. 1).

6 0
3 years ago
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