1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gavmur [86]
3 years ago
13

The back of Monique's property is a creek. Monique would like to enclose a rectangular area, using the creek as one side and fen

cing for the other three sides, to create a corral. If there is 580 feet of fencing available, what is the maximum possible area of the corral?
Mathematics
2 answers:
umka2103 [35]3 years ago
7 0

Answer:

Maximum possible area of the corral will be 42050 square feet.

Step-by-step explanation:

Monique wants to enclose a rectangular area, using creek on one side and other three sides by the fence.

Let the length of one side of the rectangular area is 'x' feet and other side is 'y'.

Length of the fencing has been given as 580 feet.

Therefore, (2x + y) = 580

2x + y = 580

y = (580 - 2x)-------(1)

Area of the rectangular area = length × width

A = xy

Now we replace the value of y in the area

A = x(580 - 2x)

   = 580x - 2x²

For the maximum area of the corral, we will find the derivative of the area A with respect to x and equate it to zero.

\frac{dA}{dx}=\frac{d}{dx}(580x-2x^{2}) = 0

580 - 4x = 0

4x = 580

x=\frac{580}{4}

x = 145 feet

From equation (1)

y = (580 - 2×145)

  = 580 - 290

  = 290 feet

Maximum area covered of the corral = xy

= 145×290

= 42050 square feet

Therefore, maximum possible area of the corral will be 42050 square feet.

kondor19780726 [428]3 years ago
3 0
So long as the perimeters are the same, rectangles and squares share the same area. For example, a square that is 2m by 2m across is 4m squared. A rectangle of 4m by 1m across is still 4m squared.

Therefore all we want to do here is see how big we can make our “square” perimeter using the creek. We have three sides to spread 580ft across, therefore if we divide this by 3, we get 193.3ft of fencing per side. If we then square this figure, we will then get the maximum possible area, which comes to 37,377ft squared. (That’s a huge garden).
You might be interested in
Which number do you add to 3 to get 0?
grandymaker [24]

Answer:

-3

Step-by-step explanation:

3 + (-3) = 0

7 0
3 years ago
Read 2 more answers
PQ is parallel to RS. The length of RP is 4cm; the length of PT is 16cm; the length of QT is 20cm. What is the length of SQ?
Step2247 [10]
Hello,

Using the theorem of Thalès,
PR/TP=QS/TQ==>QS=4*20/16=5

Answer A
3 0
3 years ago
The sum of matrices A and B is C.
GuDViN [60]

Answer:

Step-by-step explanation: -3

4 0
3 years ago
Use cramers rule to solve each system of equations :
Snowcat [4.5K]

Answer:

just follow the rules

Step-by-step explanation:

Cramer's rule applies to the case where the coefficient determinant is nonzero. ... A simple example where all determinants vanish (equal zero) but the system is still incompatible is the 3×3 system x+y+z=1, x+y+z=2, x+y+z=3.

Write the system as a matrix equation. ...

Create the inverse of the coefficient matrix out of the matrix equation. ...

Multiply the inverse of the coefficient matrix in the front on both sides of the equation. ...

Cancel the matrix on the left and multiply the matrices on the right.

5 0
2 years ago
Find the area of the shaded regions. Give your answer as a completely simplified
Pavel [41]

The area of the shaded region is 40π/3 square cm if the radius of the small circle r is 3 cm and the radius of the large circle R is 7 cm.

<h3>What is a circle?</h3>

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

We have a circle in which the shaded region is shown.

The radius of the small circle r = 3 cm

The radius of the large circle R = 3+4 = 7 cm

The area of the shaded region:

= area of the large circle sector - an area of the small circle sector

                                                     

= (120/360)[π7²] - (120/360)[π3²]

= 49π/3 - 3π

= 40π/3 square cm or

= 13.34π square cm

Thus, the area of the shaded region is 40π/3 square cm if the radius of the small circle r is 3 cm and the radius of the large circle R is 7 cm.

Learn more about circle here:

brainly.com/question/11833983

#SPJ1

5 0
2 years ago
Other questions:
  • How does Elian's drawing show that the number 10 is a composite number?
    12·1 answer
  • Bruce pitches for his little brother's baseball team. He has observed that the number of pitches a batter hits varies and is giv
    10·1 answer
  • Simplify the rational expression(picture and choices attached)! 15 points and will give Brainliest. Due soon.
    12·2 answers
  • Factor the expression 63+81
    7·1 answer
  • PLZZZZZ HELP 100 POINTS
    9·2 answers
  • A scientist uses 20 grams of carbon every 10 minutes during an experiment. If the experiment lasted 2 hours, how many total kilo
    8·2 answers
  • What are the zeros (x-intercepts) of the function y - 2x2 +7x+3?
    7·1 answer
  • If bananas are $0.50 each, how much would it cost for 7 bananas?
    8·2 answers
  • What is 3 to the power of 7 times 92 divided by 3.369
    13·1 answer
  • In a particular class of 27 students, 11 are men. What fraction of the student are men?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!