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kakasveta [241]
3 years ago
14

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = -2/5(x – 10). What is the

standard form of the equation for this line? A)2x – 5y = –15 B)2x – 5y = –17 C)2x + 5y = –15 D)2x + 5y = –17
Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0
C.
2x + 5y =  - 15
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Find the missing side of the right triangle. Round to the nearest 10th if necessary:
denpristay [2]
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Read 2 more answers
5x3 + 14x2 + 9x <br> help
Cerrena [4.2K]
<h3>Answer:    x(x+1)(5x+9) </h3>

===================================================

Work Shown:

5x^3 + 14x^2 + 9x

x( 5x^2 + 14x + 9 )

To factor 5x^2 + 14x + 9, we could use the AC method and guess and check our way to getting the correct result.

A better way in my opinion is to solve 5x^2 + 14x + 9 = 0 through the quadratic formula

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(14)\pm\sqrt{(14)^2-4(5)(9)}}{2(5)}\\\\x = \frac{-14\pm\sqrt{16}}{10}\\\\x = \frac{-14\pm4}{10}\\\\x = \frac{-14+4}{10} \ \text{ or } \ x = \frac{-14-4}{10}\\\\x = \frac{-10}{10} \ \text{ or } \ x = \frac{-18}{10}\\\\x = -1 \ \text{ or } \ x = \frac{-9}{5}\\\\

Then use those two solutions to find the factorization

x = -1  or  x = -9/5

x+1 = 0  or  5x = -9

x+1 = 0  or  5x+9 = 0

(x+1)(5x+9) = 0

So we have shown that 5x^2 + 14x + 9 factors to (x+1)(5x+9)

-----------

Overall,

5x^3 + 14x^2 + 9x

factors to

x(x+1)(5x+9)

6 0
3 years ago
What is the equation of the line that passes through the point (-6,7) and has a slope of -5? Write the equation in slope interce
Vedmedyk [2.9K]

Answer:

y = -5x - 23

Step-by-step explanation:

Point-slope form:

y - 7 = -5(x + 6)

rearrange:

y - 7 = -5x - 30

y = -5x - 23

4 0
3 years ago
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