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3 years ago

How do I solve this problem

Mathematics

1 answer:

tino4ka555 [31]3 years ago

7 0

Answer:

0.6

Step-by-step explanation:

2x3 add 1 power of 10 to the 3 you get 6 and now you just remove/divide the power of 10 you added and you get .6

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A portion of the Quadratic Formula proof is shown. Fill in the missing statement.

Zielflug [23.3K]

Answer:

Option A.

Step-by-step explanation:

we have

$x+\frac{b}{2a} =\pm\sqrt{\frac{b^2-4ac}{4a^2}}$

Simplify the right side of the equation

we know that

$\pm\sqrt{\frac{b^2-4ac}{4a^2}}=\pm\frac{\sqrt{b^2-4ac}}{\sqrt{4a^2}}=\pm\frac{\sqrt{b^2-4ac}}{2a}$

The expression is

$x+\frac{b}{2a}=\pm\frac{\sqrt{b^2-4ac}}{2a}$

therefore

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a

4 0

3 years ago

(X2)3<br> Power of a power rule

nalin [4]

2•3=6
I’m not for sure but used photomath

6 0

3 years ago

How many 60 degree angles does it take to make a full turn?

Ksenya-84 [330]

It take 6 60 degree turn to do a full turn

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3 years ago

Read 2 more answers

Suki gets a job that pays $31000 per year. she is promised a $2200 raise each year. at this rate, what will her salary be in 7 y

kiruha [24]

$232400 Money earned in the next 7 years.

Money earned per year:

$33200 = 1st year

$35400 = 2nd year

$37600 = 3rd year

$39800 = 4th year

$42000 = 5th year

$44200 = 6th year

$46400 = 7th year

5 0

3 years ago

Read 2 more answers

Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. Assume that the cost o

Snezhnost [94]

Answer:265.25

Step-by-step explanation:

Given

Volume of box $=12 m^3$

height is 3 times the width

let height, length and breadth be H, L & B

$H=3\times B$

$V=12=L\times B\times H$

4=B^2\times L[/tex]

$L=\frac{4}{B^2}$

Cost of side walls $ $8/m^2$

Cost of base $ $12/m^2$

Cost of side walls $=(2LH+2BH)\cdot 8$

Cost of base $=12LB$

Total cost $C=16LH+16BH+12LB$

$C=48LB+48B^2+12LB$

$C=\frac{192}{B}+48B^2+\frac{48}{B}$

differentiate C w.r.t B to get minimum cost

$\frac{\mathrm{d} C}{\mathrm{d} B}=-\frac{192}{B^2}+2\times 48 B-\frac{48}{B^2}$

$B^3=\frac{240}{2\times 48}$

$B=1.35 m$

$H=3\times 1.35=4.07 m$

L=2.19 m

C=$ 265.25

3 0

3 years ago