Yes because 9 is bigger than 0.
Given that question: Shyam invested money in the stock market. In the first
year, his stock increased 20%. He paid his stock broker $300 and then lost
$450. He withdrew $500, and then his remaining investment doubled. Shyam’s investment is now worth $7100. How much was Shyam’s original investment?
The solution is as follows:
Let the amount Shyam invested in the stock market be x, then in the first year his stock increased by 20% giving 1.2x.
He paid his stockbrocker $300 to have 1.2x - $300 left, and he lost $450 to have 1.2x - $300 - $450 = 1.2x - $750 left.
He withdrew $500 to have 1.2x - $750 - $500 = 1.2x - $1,250 left.
His remaining investment doubled to have 2(1.2x - $1,250) = 2.4x - $2,500
Shyam's investment is now worth $7,100 which means that
2.4x - $2,500 = $7,100
2.4x = $7,100 + $2,500 = $9,600
x = $9,600 / 2.4 = $4,000
Therefore, the value of Shyam's original investment is $4,000
Answer:
I have no clue sorry I want to kill whoever made math
1. 12 mph, 24 miles
2. m=4, y=22
3.15/1, $1500
4. x=30 y=60, k cheaper, j cheaper
We have been given the expression 2^5/8=2^2
8 can be rewritten as 2^3
Hence, the given expression becomes
2^5/2^3=2^2
After subtracting the exponents on left hand side of the equation we get:
2^2=2^2
we can do it by simplifying 8 to 2^3 to make both powers base two, and subtracting the exponents.
