Let's rewrite the equation with x and y on the left side of the equal sign.
5x-4y=8 --------(1)
3x-3y=3---------(2)
Divide equation (2) by 3,
x - y= 1
now we have,
5x-4y = 8 --------(1)
x - y = 1 ---------(2)
To eliminate x, multiply equation (2) by 5. This makes both the coefficients of x to be 5. Subtract the second equation from the first equation.
5x - 4y = 8
(2) * 5 5x - 5y = 5
(-) (+) (-)
----------------
0x +y =3
Therefore, y=3
Substitute the value of y, in any one of the two equations. Let's substitute y in the second equation.
x-3=1
x=4
x=4 and y=3
In this equation we start by filling in the N with "1" then"2" then "3" and so on
3n+4=
3(1)+4=7
3(2)+4=10
3(3)+4=13
3(4)+4=16
You said -x + 8 > 6
Subtract 8 from each side: -x > -2
Add 'x' to each side: 0 > -2 + x
Add 2 to each side: 2 > x
Now, test the choices:
A). Can 'x' be 4 ?
No. 2 is not greater than 4 .
B). Can 'x' be 1 ?
Yes. 2 is greater than 1 .
C). Can 'x' be 2 ?
No. 2 is not greater than 2 .
D). Can 'x' be 15 ?
No. 2 is not greater than 15 .
Answer:
25%
Step-by-step explanation:
So first we need to find out how many hours the school has class. Its 4 hours from 8 to noon, then another 2 from noon to 2. This means the school has class 6 hours a day.
Now we need to figure out the percent. we need to have hours of school over total hours or 6/24
6/24
we can simplify this by dividing both sides by 6
(6/6)/(24/6)=1/4
1/4 is 25%
The school holds class for 25% of the day
Given that,
Charge q₁ = -0.004 C
Charge q₂ = -0.003 C
Distance between charges, d = 3 m
To find,
The electrostatic force between charges.
Solution,
The formula for the electrostatic force is given by :
So, 12000 N of electrostatic force is produced.
