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slega [8]
2 years ago
8

PLEASE HELP PLEASE HELP

Mathematics
2 answers:
Dominik [7]2 years ago
8 0
Jenna’s belongs in C line L
Vikentia [17]2 years ago
4 0

Answer:

I think line C and L since Jenna's numbers are the same

You might be interested in
How do you solve x(x+h)=x-h for h?
WITCHER [35]

Answer: H = \frac{-x^{2}+x }{x+1}

Step-by-step explanation:

Step 1: Add h to both sides.

hx+x²+h=−h+x+h

hx+x²+h=x

Step 2: Add -x^2 to both sides.

hx+x²+h+−x²=x+−x²

hx+h=−x²+x

Step 3: Factor out variable h.

h(x+1)=−x²+x

Step 4: Divide both sides by x+1

3 0
4 years ago
Ralph has budgeted $175 for entertainment. He uses this money to go out on dates for $35 or to go out with his friends for $15.
Stolb23 [73]
Assuming that Ralph budgeted $180 instead of $175 entertainment. He spent $35 per date and let "x" be the number of dates he attended. He spent $15 to go out with friends and let "y" the number of times that he go out with friends.

The correct expression is the "B" which is 35x + 15y =180.
8 0
4 years ago
For the function f(x) = (5-6x)^2, fine f^-1
Scorpion4ik [409]

Answer:

f(-1) = 121

Step-by-step explanation:

f(x) = (5-6x)^2 (First we will substitute x for -1)

f(-1) = (5-6(-1))^2 (Then we will combine like terms)

f(-1) = (11)^2 (Then we will square it)

f(-1) = 121 (You are done)

8 0
3 years ago
Please help with the questions in the image
Pavel [41]

Answer:   f(x) = (x - 3)²

<u>Step-by-step explanation:</u>

Use the vertex formula: y = a(x - h)² + k

and input the vertex (h, k) = (3, 0) and the given point (x, y) = (4, 2) to solve for a

2 = a(4 - 3)² + 0

2 = a(1)²

2 = a

Now, input (h, k) = (3, 0) and a = 1 into the vertex formula:

y = 1(x - 3)² + 0    →     y = (x - 3)²  

****************************************************************************

Answer:   g(x) = -(x + 1.25)² + 2.5625

<u>Step-by-step explanation:</u>

Use the vertex formula: y = a(x - h)² + k

and input the given points for (x, y) to create a system of equations, then solve for a, h, and k.

EQ1: 2 = a(-2 - h)² + k  

       2 = a(4 + 4h + h²) + k

       2 - 4a - 4ah - ah² = k


EQ2: 1 = a(0 - h)² + k

        1 = ah² + k

        1 - ah² = k


EQ3: -2.5 = a(1 - h)² + k

        -2.5 = a(1 - 2h + h²) + k

        -2.5 -a + 2h + ah² = k

<u>Substitute</u> - set EQ1 = EQ2 and EQ2 = EQ3 to eliminate k

EQ1 = EQ2:     2 - 4a - 4ah - ah² = 1 - ah²

                                 1 - 4a - 4ah = 0    

EQ2 = EQ3:     1 - ah² = -2.5 - a + 2ah - ah²

                                3.5 + a - 2ah = 0  

<u>Elimination:</u>  - now solve the system for "a"

 1 - 4a - 4ah = 0    →    1(1 - 4a - 4ah = 0)    →     1 - 4a - 4ah = 0

3.5 + a - 2ah = 0   →   -2(3.5 + a - 2ah = 0) →  <u> -7 - 2a + 4ah = 0 </u>

                                                                         -6 - 6a           = 0

                                                                              -6a            = 6

<h2>                                                     a     = -1</h2>

Next, replace "a" with -1 into either of the equations to solve for "h"

                                         1 - 4a - 4ah = 0

                                     1 - 4(-1) - 4(-1)h = 0

                                            1 + 4 + 4h = 0

                                                 5 + 4h = 0

                                                       4h = -5

<h2>                                     h = -1.25</h2>

Now, replace "a" with -1 and "h" with -1.25 into any of the original equations (EQ1, EQ2, or EQ3) to solve for k:

1 - ah² = k

1 - (-1)(-1.25)² = k

1 - (-1)(1.5625) = k

1 + 1.5625 = k

<h2> 2.5625 = k</h2>

Now, input (h, k) = (-1.25, 2.5625) and a = -1 into the vertex formula:

y = -1(x - (-1.25))² + 2.5625    →     y = -(x + 1.25)² + 2.5625

4 0
4 years ago
(a) The 10 members of the swim team completed the following numbers of laps at today's practice:
Sever21 [200]

Answer:

mean

Step-by-step explanation:

8 0
3 years ago
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