HELP!!! 50 POINTS!!!! a transformation is a ___ to the _ or ___ of a figure

Mathematics

1 answer:

Temka [501]2 years ago

4 0

Answer:

a transformation is a rotation or reflection  to the position or co-ordinates of a figure

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NEED THIS TO BE CORRECT, I WILL GIVE ANYTHING!!

dolphi86 [110]

Step-by-step explanation:

3(x+2) + 35 + 52 = 180 ( Angle sum property)

3x+ 6 + 87 = 180

3x + 93 = 180

3x = 180 - 93 = 87

x= 87/ 3

x = 29

∠C = 3 ( 29 + 2)

= 3 x 31

= 93

5 0

3 years ago

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What is the area of a rectangular prism

OleMash [197]

The area of a rectangular prism would be A=2(wl+hl+hw)

I hope this helped! Mark me Brainliest! :) -Raven❤️

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3 years ago

Three less than 5 times a number is less than or equal to 12. If the number is a whole number, what could the number be?:

PIT_PIT [208]

Answer:

Step-by-step explanation:

4x2=8

5x2=10

6x2=12

This answer is the closest to 12 but it doesn't go over 12, so this is less than or equal to 12

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3 years ago

Root 3 cosec140° - sec140°=4 prove that

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

Proof:

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$