11

Use the area of the rectangle to find the area of the triangle

Alborosie

Answer is D

if you want to get the area of a triangle you have to multiply the base times height and than divide by 2

A= 1/2 bh
A=1/2 (7x6)
A= 1/2(42)
A= 21

and for the area of the rectangle it’s 42 since there’s no dividing

A=bh
A=7x6
A=42

8 0

2 years ago

Can it be solve pq(r²+1)-r(p²+q²)

ivann1987 [24]

Answer:

pqr²+pr-rp²+rq²

Step-by-step explanation:

pq(r²+1)-r(p²+q²)

pqr²+pr-rp²+rq²

3 0

1 year ago

5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.

s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of (124 and 244) and (4424 and 2111) are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

#initialize a function named gcd which takes in two parameters

if a>b:

#checks if a is greater than b

return gcd (b, a)

#if true interchange the Parameters and Recall the function

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

#even numbers leave no remainder when divided by 2, checks if a and b are even

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

#checks if a is odd and B is even

return gcd(a, b/2)

else :

return gcd(a, b-a)

#since it's a recursive function, it recalls the function with new parameters until a certain condition is satisfied

print(gcd(124, 244))

print()

#leaves a space after the first output

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0

2 years ago

Add. (3b + 5) + (2b + 4)

zaharov [31]

Answer:

$\huge{ \fbox{ \sf{5b + 9}}}$

Step-by-step explanation:

$\star{ \text{( \: 3b + 5) + (2b + 4)}}$

$\text{Step \: 1 \: : \sf{Remove \: the \: unnecessary \: parentheses}}$

$\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}$

$\text{That \: means, \: the \: expression \: remains \: the \: same. \: Just \: you \: have \: to \: remove \: the \: parentheses.}$

$\mapsto{ \sf{3b + 5 + 2b + 4}}$

$\text{Step \: 2 \: : Collect \: like \: terms.}$

$\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}$

$\mapsto{ \sf{3b + 2b + 5 + 4}}$

$\mapsto{ \sf{5b + 5 + 4}}$

$\text{ Step \: 3 \: : \sf{Add \: the \: numbers : 5 \: and \: 4}}$

$\mapsto{ \boxed {\sf{ {5b + 9}}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

4 0

2 years ago

What does it mean reflection across ×=3

Advocard [28]

You draw a vertical line on the point (3,0) and a vertical like looks like———>>> | , then whatever shape or point it gives you, you reflect off of that line like if it was a mirror

4 0

2 years ago

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