These two lines have the same rate of change
Answer:
7
Step-by-step explanation:
Calculating the z-score provides additional information regarding how each subject did overall as the z-score takes dispersion into account.
<h3>What is a z score?</h3>
Z-score indicates how much a given value differs from the standard deviation. For example, the mean of a test could be a 73 and if a student scored an 85, that's great.
However, if the data is not spread out, that 85 could be the highest in the class by 10 points. That's much more information than just 15 points above the mean. This way you can tell when someone not only did well but did exceptionally well in comparison to his or her peers.
Learn more about z score on:
brainly.com/question/25638875
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Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3
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Explanation:
There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
This assumes that m is nonnegative.
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A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative
sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
sqrt(m^6) = m^3
where m is nonnegative
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If we allow m to be negative, then the final result would be either |m^3| or |m|^3.
The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.
Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2
Step-by-step explanation:
The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:
Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.
So
Average velocity is 0.5 sec
To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.
We already found this, so I don't need more work (it's displayed above).
The instantaneous velocity when 
is 2.5 sec.
