What is the arc measure in degrees of abc on circle p in 41 degrees

Mr. Morris is going to save money and replace his sailboat's mainsail himself. He must determine the area of the mainsail in ord

kirill [66]

So, the base is 20 and you will multiply the base by the height which is 15 so if you want it with the triangles and squares then, you break down the parallelogram into 2 triangles and 1 square you will get the height of the 2 triangles and the square and add them all up and you should get 300 if you need me to explain better i will!

4 0

3 years ago

PLEASE HELP 13 MIN LEFT HELLPPPPP!!!!!!! I’ll mark brainliest

vekshin1

Answer:

D.

Step-by-step explanation:

4 0

3 years ago

Giving 20 points ;(((((()

harkovskaia [24]

Answer:

$\large\boxed{3\div\dfrac{1}{3}}$

Step-by-step explanation:

1 has been divided into three equal parts. Each of these parts is 1/3. Let's calculate how many times 1/3 is in 3.

5 0

3 years ago

Read 2 more answers

Choose the best answer:

Oksi-84 [34.3K]

Answer:

The length of the hypotenuse is 2 square root of 13 ⇒ c

Step-by-step explanation:

The rule of the area of the right triangle is A = $\frac{1}{2}$ × leg1 × leg2, where

leg1 and leg2 are the sides of the right angle

∵ The area of a right triangle is 12 in²

∵ The ratio of the length of its legs is 2: 3

→ Let leg1 = 2x and leg2 = 3x

∵ leg1 = 2x and leg2 = 3x

→ Substitute them in the rule of the area above

∴ 12 = $\frac{1}{2}$ × 2x × 3x

∵ 2x × 3x = 6x²

∴ 12 = $\frac{1}{2}$ × 6x²

∴ 12 = 3x²

→ Divide both sides by 3 to find x²

∴ 4 = x²

→ Take √ for both sides

∴ x = 2

→ Substitute x in the expressions of leg1 and leg2 to find them

∴ leg1 = 2(2) = 4 inches

∴ leg2 = 3(2) = 6 inches

∵ hypotenuse = $\sqrt{(leg1)^{2}+(leg2)^{2}}$

∴ hypotenuse = $\sqrt{(4)^{2}+(6)^{2}}=\sqrt{16+36}=\sqrt{52}$

∵ The simplest form of $\sqrt{52}$ = 2 $\sqrt{13}$

∴ The length of the hypotenuse = 2 $\sqrt{13}$ inches

3 0

3 years ago

Mr. Smith traveled to a city 300 miles from his home to attend a meeting. Due to car trouble, his average speed returning was 6

Kryger [21]

Answer: The speed at which he traveled to the city is 69.8 mph

Step-by-step explanation:

Let x represent the speed at which he traveled to the city.

Mr. Smith traveled to a city 300 miles from his home to attend a meeting.

Time = distance/speed

Time taken to travel to the city is

300/x

Due to car trouble, his average speed on returning was 6 mph less than his speed going. This means that the speed at which he returned is (x - 6) mph. Time taken to return from the city is

300/(x - 6)

If the total time for the round trip was 9 hours, it means that

300/x + 300/(x - 6) = 9

Cross multiplying by x(x - 6), it becomes

300(x - 6) + 300x = 9x(x - 6)

300x - 1800 + 300x = 9x² - 54x

9x² - 54x - 300x - 300x - 1800 = 0

9x² - 654x -1800 = 0

Applying the general quadratic equation,

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 9

b = - 654

c = 1800

Therefore,

x = [- - 654 ± √(- 654² - 4 × 9 × 1800)]/2 × 9

x = [654 ± √(427716 - 64800)]/18

x = [654 ± √362916.4]/18

x = (654 + 602.4)/2 or x = (654 - 602.4)/18

x = 1256.4/18 or x = 51.6/18

x = 69.8mph or x = 2.9 mph

The speed at which he traveled to the city is 69.8 mph

By checking,

Time spent travelling to the city = 300/69.8 = 4.3 hours

Time spent returning =

300/(69.8 - 6) = 4.7 hours

4.3 + 4.7 = 9 hours

3 0

3 years ago