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2 years ago

Can someone please check if this is correct?

Mathematics

1 answer:

Solnce55 [7]2 years ago

7 0

Answer:

Just two corrections! See attached image.

Step-by-step explanation:

The product of 8 and b taken <u>from</u> 10 means begin with 10 and subtract 8b from it.

8 times the difference of 10 and b means find 10 - b first, <u>then</u> multiply by 8.

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2 years ago

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Step-by-step explanation:

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2 years ago

Are the ratios 8:2 and 4:1 equivalent?

AysviL [449]

Answer:

Yes

Step-by-step explanation:
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2 years ago

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Rudik [331]

Answer:

y=2x-3

Step-by-step explanation:

2 is the slope/gradient

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2 years ago

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A deposit earns interest at a rate of r percent compounded continuously and doubles in value in 9 years. Find r. (Round your ans

AVprozaik [17]

Answer:

The earning rate is approximately 0.08.

Step-by-step explanation:

We can determine the yearly rate by means of compound interest, which is defined by:

$C(t) = C_{o}\cdot (1+r)^{t}$ (Eq. 1)

Where:

$C_{o}$ - Initial deposit, measured in US dollars.

$r$ - Earning rate, dimensionless.

$t$ - Earning periods, measured in years.

We proceed to clear the earning rate within:

$\frac{C(t)}{C_{o}} = (1+r)^{t}$

$\log \frac{C(t)}{C_{o}} = t\cdot \log (1+r)$

$\frac{1}{t}\cdot \log \frac{C(t)}{C_{o}} = \log (1+r)$

$\log \left(\frac{C(t)}{C_{o}} \right)^{\frac{1}{t} } = \log (1+r)$

$\left(\frac{C(t)}{C_{o}} \right)^{\frac{1}{t} } = 1+r$

$r = \left(\frac{C(t)}{C_{o}} \right)^{\frac{1}{t} }-1$

If we know that $C(9) = 2\cdot C_{o}$ and $t = 9$ , then the earning rate is:

$r = 2^{\frac{1}{9} }-1$

$r \approx 0.08$

The earning rate is approximately 0.08.

8 0

2 years ago