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Romashka [77]
2 years ago
9

mr.roxbury weighed 240 pounds when he started on a diet. over a one year period mr.roxbury lost 32% of his body weight. in the f

ollowing year, he gained 15% back of his post diet body weight about how many pounds does mr.roxbury weigh after the two year leriod​
Mathematics
1 answer:
Annette [7]2 years ago
3 0

Answer:

187.68

Step-by-step explanation:

240*.32=76.8

240-76.8=163.2

163.2*.15=24.48

163.2+24.48=187.68

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A student drove to the university from her home and noted that the odometer reading of her car increased by 16.0 km. The trip to
notka56 [123]

Answer:

Average speed is 48 km per hour

Step-by-step explanation:

A student drove to the university from her home and noted that the odometer reading of her car increased by 16.0 km. The trip took 20.0 min. (a) What was her average speed? in km/hr

Distance traveled is 16 km and the time taken is 20 minutes

convert minutes into hour. to convert minutes into hour we divide by 60 because 1 hour = 60 minutes

\frac{20}{60} =\frac{1}{3}

so time = 1/3  and distance = 16

Average speed = distance by time

speed =\frac{16}{\frac{1}{3} } =\frac{48}{1}= 48

Average speed is 48 km per hour

4 0
3 years ago
Look at the expression 15 + 75. Write an expression that shows the GCF multiplied by the sum of the other factors. 
skelet666 [1.2K]
The answer to that question would be 15
8 0
2 years ago
Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe
icang [17]

Answer:

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

  h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

  h(-1) = 8(-1)²(-1-3) = -32

  h(0) = 8(0)(0-3) = 0

  h(2) = 8(2²)(2 -3) = -32

  h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum

_____

Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.

5 0
3 years ago
Solve for x:<br>log x + log 8 = 2<br>​
likoan [24]

Answer: The answer is 252

Step-by-step explanation:

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2 years ago
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svp [43]

Answer:

C

Step-by-step explanation:

from some other question so thank this guy

Frika

6 0
3 years ago
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