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DENIUS [597]
3 years ago
9

Pearson Electric Company uses the high-low method to analyze mixed costs. The following information relates to the production da

ta for the first six months of the year. Month Cost(Y) Hours(H) January $ 7,300 260 February $ 9,125 730 March $ 7,540 410 April $ 7,485 330 May $ 9,460 980 June $ 9,030 705 How should the cost function be properly stated using the high-low method?
Business
1 answer:
Simora [160]3 years ago
8 0

Answer: 6520 + 3x

Explanation:

Firstly, we need to calculate the variable cost per hour which will be:

= (Highest activity cost – Lowest activity cost)/(Highest activity hour – Lowest activity hour)

= (9460 - 7300)/(980 - 260)

= 2160 / 720

= 3

We'll also find the fixed cost which will be:

= Fixed cost = Highest activity cost – (Variable cost per hour x Highest activity hour)

= 9460 - ( 3 x 980)

= 9460 - 2940

= 6520

Therefore, the cost function will be:

= 6520 + 3x

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Reality Entertainment, Inc is a major producer of reality TV programming. The company faces tough competition from three other m
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Read 2 more answers
The given data represent the total compensation for 10 randomly selected CEOs and their​ company's stock performance in 2009. An
jok3333 [9.3K]

Missing Question Data:

As the Question is missing relevant data, I have searched for it online and found a question similar. The data is attached in a picture file. It might be a little different from your actual question but same approach can be used to solve the question.

Answer with Explanation:

For simplicity, we denote the compensations with variable <em>x </em>and the stock return with variable <em>y.</em> Let us first find the mean and standard deviation for both compensation (x) and return (y).

Mean of Compensation (<em>x) </em> will be,

X\;=\;\frac{26.43\;+\;12.03\;+\;19.74\;+\;13.54\;+\;11.97\;+\;11.41\;+\;25.94\;+\;14.46\;+\;17.13\;+\;14.71}{10}

X\; = \;16.737

Mean of Stock Return (y) will be,

Y\;=\;\frac{5.43\;+\;30.89\;+\;31.89\;+\;80.06\;-\;8.22\;+\;2.89\;+\;4.39\;+\;10.95\;+\;4.18\;+\;11.94}{10}

Y\;=\;17.44

Standard Deviation for Compensation (x) is given by,

\sigma _{x}\;=\;\sqrt{\frac{\sum (x_{i}-X)^{2}}{N}}

\sigma _{x}\;=\;\sqrt{\frac{(26.43-16.73)^{2}+(12.03-16.73)^{2}+....+(14.71-16.73)^{2}}{10}}

\sigma _{x}\;=\;5.30

Standard Deviation for Compensation (x) is given by,

\sigma _{y}\;=\;\sqrt{\frac{\sum (y_{i}-Y)^{2}}{N}}

\sigma _{y}\;=\;\sqrt{\frac{(5.43-17.44)^{2}+(30.89-17.44)^{2}+....+(11.94-17.44)^{2}}{10}}

\sigma_{y}\;=\;23.97

To find the predicted stock return, we have to use the equation for of line of regression,

y_{required}\;-\;Y\;=\;z\;*\;\frac{\sigma _{x}}{\sigma _{y}}\;*\;(x_{required}-X)\;.........\;(1)

where,

z\; =\;Correlation\;coefficient\;=\;-0.2426\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;(given)

x_{required}\;=\;Compensation\;of\;\$15\;million\;=\;15

y_{required}\;=\;Stock\;return\;at\;x_{required}

Equation (1) will become,

y_{required}\;-\;17.44\;=\;-0.2426\;*\;\frac{5.30}{23.97}\;*\;(15\;-\;16.73)

y_{required}\;=\;-0.054*\;(-1.73)\;+\;17.44\;

y_{required}\;=\;17.533.

4 0
3 years ago
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