Ask question

Ask question

All categories

3 years ago

13

A company's flexible budget for the range of 35,000 units to 45,000 units of production showed variable overhead costs of $3.80

per unit and fixed overhead costs of $74,000. The company incurred total overhead costs of $209,800 while operating at a volume of 40,000 units. The total controllable cost variance is:Multiple Choice$16,200 unfavorable.$10,000 favorable.$2,800 unfavorable.$2,800 favorable.$16,200 favorable.

1 answer:

Dima020 [189]3 years ago

3 0

Answer:

$16,200 favorable

Explanation:

The computation of the total controllable cost variance is shown below:

= Budgeted overhead - actual overhead

= (40,000 units × $3.80 + $74,000) - $209,800

= ($152,000 + $74,000) - $209,800

= $226,000 - $209,800

= $16,200 favorable

Hence, the total controllable cost variance is $16,200 favorable

You might be interested in

Show that the set of vectors {(−4,1,3),(5,1,6),(6,0,2)} does not span R 3 , but that it does span the subspace of R 3 consisting

Alika [10]

Answer:

The vectors does not span R3 and only span a subspace of R3 which satisfies x+13y-3z=0

Explanation:

The vectors are given as

$v_1=\left[\begin{array}{c}-4&1&3\end{array}\right] \\v_2=\left[\begin{array}{c}-5&1&6\end{array}\right] \\v_3=\left[\begin{array}{c}6&0&2\end{array}\right]$

Now if the vectors would span the $R^3$ , the rank of the consolidated matrix will be 3 if it is not 3 this indicates that the vectors does not span the $R^3$ .

So the matrix is given as

$M=\left[\begin{array}{ccc}v_1&v_2&v_3\end{array}\right] \\M=\left[\begin{array}{ccc}-4&5&6\\1&1&0\\3&6&2\end{array}\right]\\$

In order to calculate the rank, the matrix is reduced to the Row Echelon form as

$\approx \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{9}{4}&\frac{3}{2}\\ 3&6&2\end{array}\right] R_2 \rightarrow R_2+\frac{R_1}{4}$

$\approx \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{9}{4}&\frac{3}{2}\\ 0&\frac{39}{4}&\frac{13}{2}\end{array}\right] R_3 \rightarrow R_3+\frac{3R_1}{4}\\$

$\approx \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{39}{4}&\frac{13}{2\\ 0&\frac{9}{4}&\frac{3}{2}}\end{array}\right] R_2\:\leftrightarrow \:R_3$

$\approx \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{39}{4}&\frac{13}{2}\\ 0&0&0\end{array}\right] R_3 \rightarrow R_3-\frac{3R_2}{13}\\$

As the Rank is given as number of non-zero rows in the Row echelon form which are 2 so the rank is 2.

Thus this indicates that the vectors does not span $R^3$

<em>Now for any vector the corresponding equation is formulated by using the combined matrix which is given as for any arbitrary vector and the coordinate as </em>

<em /> $v=\left[\begin{array}{c}x&y&z\end{array}\right]$ <em />

<em /> $c=\left[\begin{array}{c}c_1&c_2&c_3\end{array}\right]$ <em />

<em /> $Mc=v$ <em />

<em /> $\left[\begin{array}{ccc}-4&5&6\\1&1&0\\3&6&2\end{array}\right]\left[\begin{array}{c}c_1&c_2&c_3\end{array}\right]=\left[\begin{array}{c}x&y&z\end{array}\right]$ <em />

<em /> $M=\left[\begin{array}{ccccc}v_1&v_2&v_3& | &v\end{array}\right] \\M=\left[\begin{array}{ccccc}-4&5&6&|&x\\1&1&0&|&y\\3&6&2&|&z\end{array}\right]\\$ <em />

Now converting the combined matrix as

$\approx \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{9}{4}&\frac{3}{2}&|&\frac{4y+x}{4}\\ 3&6&2&|&z\end{array}\right] R_2 \rightarrow R_2+\frac{R_1}{4}\\$

$\approx \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{9}{4}&\frac{3}{2}&|&\frac{4y+x}{4}\\ 0&\frac{39}{4}&\frac{13}{2}&|&\frac{4z+3x}{4}\end{array}\right] R_3 \rightarrow R_3+\frac{3R_1}{4}\\$

$\approx \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{39}{4}&\frac{13}{2}&|&\frac{4z+3x}{4}\\ 0&\frac{9}{4}&\frac{3}{2}&|&\frac{4y+x}{4}\end{array}\right] R_3 \leftrightarrow R_2\\$

$\approx \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{39}{4}&\frac{13}{2}&|&\frac{4z+3x}{4}\\ 0&0&0&|&\frac{13y+x-3z}{13}\end{array}\right] R_3 \rightarrow R_3-\frac{3R_2}{13}\\$

From this it is seen that whatever the values of the coordinates does not effect the value of the plane with equation as

$\frac{13y+x-3z}{13}=0\\or\\13y+x-3z=0\\$

So it is verified that the subspace of R3 such that it satisfies x+13y-3z=0 consists of all vectors.

<em />

6 0

3 years ago

On January 1, 2020, Tamarisk Co. leased a building to Carla Vista Inc. The relevant information related to the lease is as follo

pashok25 [27]

Answer:

martphones are a type of handheld computer that do not need input, output, processing, or storage.

Explanation: sasas

8iksa

6 0

3 years ago

Highlight four ways of improving productivity of labour as a factor of production

UNO [17]

Answer:

Following are the four ways for improving the productivity of the labour is given below

Explanation:

If we give the proper resource assignment to each worker at the proper time we will increase the productivity of the labor .
Increasing the skills by guiding the labor to the latest technology so they know the latest or the current technology they will increase the productivity .
If we enhancing the physical capital it means if we dependent on the machinery they will increase the productivity .
Giving the incentive to labor at the particular interval of time we will increase the productivity.

3 0

3 years ago

Your company wants to set aside a fixed amount every year to a sinking fund to replace a piece of industrial equipment costing $

olga2289 [7]

Answer:

$4,5243.63

Explanation:

Data provided in the question:

Future value = $250,000

Interest rate = 5% = 0.05

Time = 5 years

Now,

Future value = $C\times\left[ \frac{(1+i)^{n}-1}{i} \right]$

here,

C = Regular deposit amount

i = Interest rate per period

n = number of periods

Future value = $C\times\left[ \frac{(1+i)^{n}-1}{i} \right]$

or

$250,000 = $C\times\left[ \frac{(1+0.05)^{ 5}-1}{ 0.05} \right]$

$250,000 = $C\times\left[ \frac{ 1.05^{ 5}-1}{ 0.05} \right]$

$250,000 = $C\times\left[ \frac{ 1.276282 - 1}{ 0.05} \right]$

$250,000 = C × 5.52564

or

C = $\frac{ 250000 }{ 5.52564 }$

C = $4,5243.63

7 0

4 years ago

Exercise 14-04 On October 31, the stockholders’ equity section of Cullumber Company consists of common stock $370,000 and retain

djverab [1.8K]

Answer:

Explanation:

1. Before action

The company is having the 37000 shares of $10 each outstanding.

Par value of outstanding shares = $10 * 37000 shares = $370,000

Common stock in excess of par = Total common stock - Par value of outstanding shares = $370,000 - $370,000 = 0

2. After stock dividennd

Stock dividend declared = 6% of 37,000 shares = 2,220 shares

Current market price of shares = $16 per share

Value of stock dividend declared = $16 * 2,220 = $35,520

Common stock in excess of par = $35,520 - $22,200 = $13,320

Total number of shares outstanding = 37,000 + 2,220 = 39,220

Total par value of common stock = 39,220 * $10 = $3,92,200

The stock dividend is declared out of the retained earnings.

Retained earnings after stock dividend = $904,000 - $35,520 = $868,480

3. After stock split

In this case, there is no financial impact. Only, the number of shares will get double because one share is split into two shares.

No. of outstanding shares = 37000 * 2 = 74000 shares

4 0

4 years ago