The price of a staff ticket and the price of a student ticket is $8 and $14
Given:
Day 1:
Number of staff tickets sold = 3
Number of students tickets sold = 1
Total revenue day 1 = $38
Day 2:
<em>Number of staff tickets sold</em> = 3
<em>Number of students tickets sold</em> = 2
<em>Total revenue day</em> 2 = $52
let
<em>cost of staff tickets</em> = x
<em>cost of students tickets</em> = y
The equation:
<em>3x + y = 38 (1)</em>
<em>3x + y = 38 (1)3x + 2y = 52 (2)</em>
subtract (1) from (2)
2y - y = 52 - 38
y = 14
substitute y = 14 into (1)
3x + y = 38 (1)
3x + 14 = 38
3x = 38 - 14
3x = 24
x = 24/3
x = 8
Therefore,
cost of staff tickets = x
= $8
cost of students tickets = y
= $14
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brainly.com/question/22940808
Answer:
5(3√x) +9(3√x) = 15√x+27√x= 42√x
5∛x + 9∛x = 14∛x
Step-by-step explanation:
Answer:
Trapezoid
Quadrilateral
Step-by-step explanation:
9x40= 360
9x30= 270 so the common factor is 9 I have no idea about the exponent stuff
The explanatory variable is the amount of exposure the student is given to classical music.
