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hichkok12 [17]
3 years ago
9

If 8 measures 119 what is the sum 1 and 4

Mathematics
1 answer:
kompoz [17]3 years ago
8 0
7l5     3l1
8l6     4l2
 Parallel 

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Please help me find x
Ghella [55]

Answer:

x = 53

Step-by-step explanation:

Remember that the sum of all 3 interior angles in a triangle is 180∘ so

74 + x + x = 180

74 + 2x = 180

2x = 180 - 74

2x = 106

x = 106/2

x = 53

3 0
3 years ago
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Mathwiz wya?? pic below i need help asap
n200080 [17]

Answer:

Step-by-step explanation:

First, you gotta work out the hypotenuse of ABC, which is AC.

To do that, you need to figure out the scale factor between the two right-angled triangles. You can do that for this question because this is a similar shapes question.

12.5/5 = 2.5

The scale factor length between the two triangles is 2.5.

You can use 2.5 now to work out AC, so AC would be 13 x 2.5, which gives 32.5.

Now that you've got the hypotenuse and BC of ABC, you can use Pythagoras's theorem to work out the length of AB

Pythagoras's theorem = a^2 + b^2 = c^2

a = BC = 12.5

b = AB = we need to work this out

c = AC (the hypotenuse we just worked out) = 32.5

12.5^2 + b^2 = 32.5^2 Let's both simplify and rearrange this at the same time so that we have our b on one side.

b^{2} = 1056.25 - 156.25

b = \sqrt{(1056.25 - 156.25)}

b = \sqrt{900}

b = AB = 30  We've found b or AB, now we can work out the perimeter of ABC.

Perimeter of ABC = AB + BC + AC

= 30 + 12.5 + 32.5

= 75  Here's the perimeter for ABC.

8 0
3 years ago
If a system of equations has no solution, what does the graph look like?
Valentin [98]

Answer:

Step-by-step explanation:

parallel lines

5 0
3 years ago
Read 2 more answers
What's the median of these numbers:<br> 14,20,24,16,20,18
faltersainse [42]
The answer to this is 19. The reason why is because the median falls between 18 and 20. After that, you have to take the middle number that falls between 18 and 20. In this case, 19. 
4 0
3 years ago
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The accompanying data represent the miles per gallon of a random sample of cars with a​ three-cylinder, 1.0 liter engine.a. Comp
Kobotan [32]

Answer:

1). Z score = 1.464733

Mean = 38.87917

Standard deviation = 3.609405

2). Quartiles:

Q1 = 37.025

Q2 = 38.450

Q3 = 40.800

3). IQR = 3.775

4).

CI (lower fence) = 37.4351

CI (upper fence) =  40.32323

5). There is outlier in the data set. Please see attached box plot for evidence.

Step-by-step explanation:

1). By Z score, we mean:

Z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}},

where:

x-bar ==> mean(g) = 38.87917

\mu = 37.80

standard deviation = 3.609405

sample size (n) = 24.

2). By quantile, we mean:

Q = L + (i*(n/4) - Cf)*c

Where L is the lower class limit of the quartile class

Cf is the cumulative frequency before the quartile class

c  is the class size.

3) . IQR = Q3 - Q1

4). CI = \mu \pm *Z_{\alpha/2} \frac{\sigma}{\sqrt{n}},

Where Z_{\alpha/2}  ==> 1.96

In order to replicate and obtain the result, please use the R code below:

g = c(31.5, 36.0, 37.8, 38.5, 40.1, 42.2,34.2, 36.2, 38.1, 38.7, 40.6, 42.5,34.7, 37.3, 38.2, 39.5,  

41.4, 43.4,35.6, 37.6, 38.4, 39.6, 41.7, 49.3)

boxplot(g)

Z = (mean(g) - 37.8)/(sd(g)/sqrt(length(g)))

mean(g)

quantile(g)

IQR(g)

CIl = mean(g) - 1.96*(sd(g)/sqrt(length(g)))

CIU = mean(g) + 1.96*(sd(g)/sqrt(length(g)))

4 0
3 years ago
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