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fgiga [73]
3 years ago
5

Math can you help me Fast

Mathematics
1 answer:
Andrew [12]3 years ago
7 0
I don’t know ..............
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At the start of the week, you could run for 8 minutes. By the end of the week, you could run for 15 minutes. Which proportion co
pantera1 [17]

Answer:

See below.

Step-by-step explanation:

Increase = 15 - 8 = 7 minutes.

Percent increase = 7/8 * 100.

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4 years ago
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PLEASE HELP!!!!
Fed [463]
In short, a horizontal translation, means f("x + some number"),

now, that number is 2, and is to the left, so that means f(x + 2)

\bf \begin{cases}
f(x)=-4x+3\\
g(x)=f(x+2)
\end{cases}
\\\\\\
f(x+2)=-4(x+2)+3\implies f(x+2)=-4x-8+3
\\\\\\
f(x+2)=-4x-5\impliedby g(x)
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3 years ago
Please help me on this problem! ​
USPshnik [31]

There is no solution since the lines are parallel. (See attached graph)

<h2><u><em>Hope this helps!</em></u></h2>

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Which angle is DEF has the largest measure?
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Use Brainly to find the right answer :) tha the what I do all the time
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3 years ago
a set of average city temperatures in december are normally distributed with a mean of 16.3°C and a standard deviation of 2°C. w
koban [17]

Answer:

19.74% of temperatures are between 12.9°C and 14.9°C

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16.3, \sigma = 2

What proportion of temperatures are between 12.9°C and 14.9°C?

This is the pvalue of Z when X = 14.9 subtracted by the pvalue of Z when X = 12.9.

X = 14.9

Z = \frac{X - \mu}{\sigma}

Z = \frac{14.9 - 16.3}{2}

Z = -0.7

Z = -0.7 has a pvalue of 0.2420

X = 12.9

Z = \frac{X - \mu}{\sigma}

Z = \frac{12.9 - 16.3}{2}

Z = -1.7

Z = -1.7 has a pvalue of 0.0446

0.2420 - 0.0446 = 0.1974

19.74% of temperatures are between 12.9°C and 14.9°C

3 0
3 years ago
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