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3 years ago

PLEASE HELP!!!!

1 answer:

6 0

In short, a horizontal translation, means f("x + some number"),

now, that number is 2, and is to the left, so that means f(x + 2)

$\bf \begin{cases}
f(x)=-4x+3\\
g(x)=f(x+2)
\end{cases}
\\\\\\
f(x+2)=-4(x+2)+3\implies f(x+2)=-4x-8+3
\\\\\\
f(x+2)=-4x-5\impliedby g(x)$

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The sum of two numbers is 240. If one number is twice the other number, find the two numbers.

Deffense [45]

Answer:

The sum of two numbers is 240. The larger number is 6 less than twice the smaller. Find the numbers.

----------

Let the smaller be "x" ; Larger is "2x-6"

EQUATION:

x + 2x-6 = 240

3x= 246

x = 82 (smaller)

2x-6 = 158 (larger)

Step-by-step explanation:

7 0

3 years ago

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2 years ago

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2 years ago

Solve for x: 3/2+1/2x=2x

kotykmax [81]

Answer:

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Step-by-step explanation:

3/2+1/2x=2x

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3 0

3 years ago

How do you solve cos(pi/24) using Half-Angle formulas, and leaving in simplified form?

adoni [48]

$\cos \frac{\theta}{2}=\sqrt{\frac{1+\cos \theta}{2}}
\\
\\ \cos{\frac{\pi}{24}}=\cos{\frac{\frac{\pi}{12}}{2}}=\sqrt{\frac{1+\cos \frac{\pi}{12}}{2}}= \sqrt{ \frac{1}{2}+ \frac{\cos \frac{\pi}{12}}{2} } 
\\
\\ \cos{\frac{\pi}{12}}=\cos{\frac{\frac{\pi}{6}}{2}}=\sqrt{\frac{1+\cos \frac{\pi}{6}}{2}}= \sqrt{ \frac{1}{2}+ \frac{ \frac{ \sqrt{3} }{2} }{2} } =\sqrt{ \frac{2}{4}+ \frac{ \sqrt{3} }{4} } = \sqrt{\frac{ 2+\sqrt{3} }{4} } = 
\\
\\ =\frac{ \sqrt{2+\sqrt{3}} }{2} 
$

$\cos{\frac{\pi}{24}}= \sqrt{ \frac{1}{2}+ \frac{\cos \frac{\pi}{12}}{2} } = \sqrt{ \frac{1}{2}+ \frac{\frac{ \sqrt{2+\sqrt{3}} }{2}}{2} } = \sqrt{ \frac{2}{4}+ \frac{ \sqrt{2+\sqrt{3}} }{4}} } =\sqrt{ \frac{ 2+\sqrt{2+\sqrt{3}} }{4}} } 
\\
\\\cos{\frac{\pi}{24}}=\frac{\sqrt{2+\sqrt{2+\sqrt{3}}}} {2}$

6 0

3 years ago