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Lady_Fox [76]
3 years ago
12

M∠2 = by the . m∠1 = by the . m∠3 = by the .

Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0
What are we suppose to say
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You want to see if playing music makes plants grow taller. What is the dependent variable in this experiment?
Sladkaya [172]

Answer: the hight of the plant is the dependent variable bc the independent variable is music being played

hoped this helped (let me know if it did) :)

5 0
3 years ago
Thanks for the help!
NikAS [45]

Answer:

A

Step-by-step explanation:

So we have the piecewise function:

f(x)= \begin{cases}\sqrt{2x} & \text{if }x

And we want to find f(8).

Since our input value is 8, choose the equation that fits our input.

The first equation demand x to be less than 3. 8 is not less than 3, so we won't use that.

The second equation demand x to e greater than or equal to 3 and less than 8. 8 is <em>not</em> less than 8. So, we won't use that.

The third equation demands x to be greater than or equal to 8. 8 is greater than or equal to 8, so we'll use the third equation.

So:

f(x)=42\text{ if }x\geq 8

f(8)=42

There're nothing more to do, we're done :)

The answer is A.

Edit: Improved Format

3 0
4 years ago
Please help me and show work
borishaifa [10]

Answer:

2/5

Step-by-step explanation:

If we convert 1/2 to tenths we get 5/10. We can subtract that from 9/10 to find out what q equals which will give us 4/10 which is also equal to 2/5

(sorry i'm really bad at explaining but I hope this helps)

5 0
3 years ago
Lin's job pays $8.25 an hour plus $10 of transportation allowance each week. She has to work at least 5 hours a week to keep the
Usimov [2.4K]
Y=8.25x+10

10 is the allowance plus the 8.25 times x which is the hours
5 0
3 years ago
Find the limit of the function by using direct substitution.
Pavel [41]

ANSWER

lim_{x \to \: 0}( {x}^{2} - 1)  =  - 1

EXPLANATION

The given limit is

lim_{x \to \: 0}( {x}^{2} - 1)

To evaluate this limit by direct substitution,

We put x=0 in the function.

This implies that that ,

lim_{x \to \: 0}( {x}^{2} - 1)  =  {0}^{2}  - 1

This simplifies to,

lim_{x \to \: 0}( {x}^{2} - 1)  = 0 - 1

lim_{x \to \: 0}( {x}^{2} - 1)  =  - 1

This means that as x-values approach zero, the function approaches -1.

7 0
3 years ago
Read 2 more answers
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