Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
Part a: subtract 48-30=18
Part b: i found it by subtracting 48 -30 because it says left over
Answer:
3.93700787402, almost 4
Step-by-step explanation:
10 ÷ 2.54
3 × 2.50 = 7.50
3 × 0.04 = 0.12
7.50 + 0.12 = 7.65
7.65 + 2.54 = 10.19
The precise number is use calculator.
If you have a picture that shows line c on a graph, you could find your y-intercept or b. If not, you need the y-intercept to make an equation.
Answer:
163 - p = 291
Step-by-step explanation:
