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UkoKoshka [18]
3 years ago
9

PLS HELP!!! I NEED THIS NOW!!!

Chemistry
2 answers:
Grace [21]3 years ago
7 0
It’s 42!! Let me know if this helps!
vesna_86 [32]3 years ago
6 0

Answer:

42 hope it helped !!!!!!!!!!!!

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How you could use the scientific method to learn whether water really does take longer to boil if you are watching it.
Degger [83]

Answer:

What you need is a thermometer and a clock.

Explanation:

6 0
4 years ago
How are compound, elements, and mixure different
Fofino [41]

Explanation:

Compound: a substance that is made up of more than 1 type of atom bonded together Example: H2O

Mixture: combination of two or more elements or compounds not chemicaly bonded together. example: Sugar and salt in one container

elements pure substance of an atom. Example: hydrogen

6 0
4 years ago
(a) Calculate the mass percentage of NaCl in a solution containing 1.50 g of NaCl in 50.0 g of water. (b) A commercial bleaching
stepan [7]

Answer:

a) 2.91%

b) 90.5 grams

Explanation:

Mass percentage is

mass%=\frac{massofsoluteX100}{massofsolute+massofsolvent}

a) the mass of NaCl = 1.50g

The mass of water = 50.0 g

Total mass =1.5+50=51.50 g

mass% = \frac{1.5X100}{50+1.5}=2.91 %

b) the mass percent of NaOCl = 3.62 %

It means the mass of NaOCl in 100g of bleaching solution  3.62 g

so mass of NaOCl in 2.50kg = 0.0905 kg = 90.5g

7 0
3 years ago
What happens to the temperature inside the terrarium?
stiks02 [169]

Answer:

it drops?

Explanation:

8 0
3 years ago
what is the amount of heat energy released when 50.0 grams of water is cooled from 20.0 degrees Celcius to 10.0 degrees celcius
andre [41]

Answer:

The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to  - 2093 J.

Explanation:

Given data:

Mass of water = 50 g

Initial temperature= T1 = 20°C

Final temperature= T2 = 10°C

Specific heat of water= c = 4.186 J/g. °C

Amount of heat released = Q= ?

Solution:

Formula:

Q = m. C.  ΔT

ΔT = T2 - T1

ΔT = 10°C - 20°C

ΔT = -10°C

Now we will put the values in formula.

Q = m. C.  ΔT

Q = 50 g .  4.186 J/g. °C . -10°C

Q =  - 2093 J

The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to  - 2093 J.

6 0
3 years ago
Read 2 more answers
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