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max2010maxim [7]
3 years ago
9

I'm in 5th grade and need help with and ​

Mathematics
2 answers:
patriot [66]3 years ago
4 0

Answer:

11046.4

Step-by-step explanation:

Cloud [144]3 years ago
3 0

Answer:

the answer is 11046.4

Step-by-step explanation:

if u can pls can u give me brainiest  

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What is Arithmetic Series
klio [65]

Answer:

I am pretty sure it is when you have a sequence of numbers that you are subtracting or adding from by the same constant over and over

Step-by-step explanation:

an=a1+(n-1)d

d=common difference

an= the nth term in the sequence

a1 first term in the sequence. (Usually you can plug in 1, as the n, and work from there)

4 0
3 years ago
Please answer it due tonight
madam [21]

Answer:

the value of angle W = 81° and x = 35°

Step-by-step explanation:

the explanation is in the attached picture

3 0
3 years ago
Read 2 more answers
Solve for yyy. -3 = 7\left(y-\dfrac97\right)−3=7(y− 7 9 ​ )minus, 3, equals, 7, left parenthesis, y, minus, start fraction, 9, d
Leni [432]

Answer:

y = 6/7

Step-by-step explanation:

The equation given is:

-3 = 7(y - 9/7)

To solve this, we will expand the bracket and afterwards, collect like terms:

-3 = (7*y) - (9/7 * 7)

-3 = 7y - 9

Collecting numeric terms to the left hand side:

-3 + 9 = 7y

=> 6 = 7y

=> y = 6/7

That is the solution.

3 0
4 years ago
Read 2 more answers
Evaluate the given integral by changing to polar coordinates. sin(x2 + y2) dA R , where R is the region in the first quadrant be
Leona [35]

In polar coordinates, the region R is the set of points

\left\{(r,\theta)\mid3\le r\le5,\,0\le\theta\le\dfrac\pi2\right\}

and we have x^2+y^2=r^2 and \mathrm dA=r\,\mathrm dr\,\mathrm d\theta. So the integral, converted to polar, is

\displaystyle\iint_R\sin(x^2+y^2)\,\mathrm dA=\int_0^{\pi/2}\int_3^5r\sin r^2\,\mathrm dr\,\mathrm d\theta=\frac\pi2\int_3^5r\sin r^2\,\mathrm dr

Substitute s=r^2 to get

=\displaystyle\frac\pi4\int_9^{25}\sin s\,\mathrm ds=\frac{(\cos9-\cos25)\pi}4

5 0
4 years ago
Two linear functions are shown.
sasho [114]

Answer:

Function A has a greater initial value because the initial value for Function A is 6 and the initial vale for Function B is 3

Step-by-step explanation:

The data for Function A is presented here as follows;

\begin{array}{cc}x&y\\-1&9\\0&6\\1&3\\2&0\end{array}

The slope of the function, 'm', is given using any two points as follows;

m = (9 - 3)/((-1) - 1) = -3

The slope of the function = -3

The equation of function in point and slope form is given as follows;

y - 3 = -3·(x - 1)

The equation of Function A, is therefore, given as follows;

y = 3 - 3·x + 3 = 6 - 3·x

∴ y = 6 - 3·x

The equation of Function B is given as follows;

y = 6·x + 3

The initial value of a function is given by the y-intercept of the function, where the input variable (x-variable) is zero

The initial value, (y-intercept) of Function A, f(0) is therefore found as follows;

f(x) = y = 6 - 3·x

f(0) = 6 - 3×0 = 6

The initial value of Function A, f(0) = 6

Similarly, the initial value, (y-intercept) of Function B, f(0) is found as follows;

f(x) = y = 6·x + 3

f(0) = 6×0 + 3 = 3

The initial value of the Function B, f(0) = 3

Therefore, we have that Function A has a greater initial value than Function B

8 0
3 years ago
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