Answer:
0.903264
Step-by-step explanation:
Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.
Let A' = the event that A fails, B' = B fails and C'= C fails.
Probability that no circuit board fails = Prob (A'B'C')
= P(A')P(B')P(C') (since A,B, C are independent, their complements are independent
= (1-0.03)(1-0.04)(1-0.03)
= 0.903264
Answer:
Second choice:


Fifth choice:


Step-by-step explanation:
Let's look at choice 1.


I'm going to subtract 1 on both sides for the first equation giving me
. I will replace the
in the second equation with this substitution from equation 1.

Expand using the distributive property and the identity
:




So this not the desired result.
Let's look at choice 2.


Solve the first equation for
by dividing both sides by 2:
.
Let's plug this into equation 2:



This is the desired result.
Choice 3:


Solve the first equation for
by adding 3 on both sides:
.
Plug into second equation:

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:



Not the desired result.
Choice 4:


I'm going to solve the bottom equation for
since I don't want to deal with square roots.
Add 3 on both sides:

Divide both sides by 2:

Plug into equation 1:

This is not the desired result because the
variable will be squared now instead of the
variable.
Choice 5:


Solve the first equation for
by subtracting 1 on both sides:
.
Plug into equation 2:

Distribute and use the binomial square identity used earlier:



.
This is the desired result.
Answer: 239
Step-by-step explanation:
![g(7)=2(7)-5=9\\\\f[g(7)]=f(9)=3(9)^2 - 4=239](https://tex.z-dn.net/?f=g%287%29%3D2%287%29-5%3D9%5C%5C%5C%5Cf%5Bg%287%29%5D%3Df%289%29%3D3%289%29%5E2%20-%204%3D239)