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FinnZ [79.3K]
3 years ago
14

HELP ME PLEASE!

Mathematics
1 answer:
Delicious77 [7]3 years ago
7 0
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides).  If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.

Let's see whether they do.

8^2 + 8^2 = 11^2  ???
 64    + 64 = 121?  NO.  This is not a right triangle.

If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:

8^2 + 8^2 = d^2, where d=hypotenuse.  Then 64+64 = d^2, and 

d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.

11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
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Answer:

<h3>This means that about 21 level truck loads are necessary to remove all dirts.</h3>

Step-by-step explanation:

To get the number of level truck loads needed to remove all the dirts in the house, first we need to calculate volume of the truck and the house.

Volume of truck = Length * Breadth * Height

If the truck is 5.0 for the length 2.0 for the height 3.0 for the side base;

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Volume of house = Length * Breadth * Height

If the house is 4.0 for the height 14.5 for the length and 11.0 for the side base, then

Volume of the house = 4*14.5*11 = 638

Number of level truck loads needed to remove all the dirts = Volume of house/Volume of the truck = 638/30 ≈ 21.3

This means that about 21 level truck loads are necessary to remove all dirts.

8 0
3 years ago
Could someone please show me the steps to get this answer?
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Start with f(x) = (x-9)/(x+5) and g(x) = (-5x-9)/(x-1).  To obtain f(g(x)), throw out each appearance of x in f(x) = (x-9)/(x+5) and replace it with <span>g(x) = (-5x-9)/(x-1):

f(g(x)) = [</span>(-5x-9)/(x-1) - 9] / [<span>(-5x-9)/(x-1) + 5]

Now simplify the algebra.  If your result equals just x, then you have proven that f and g are inverses of one another.  Need help with the fractions?  If so, do what you can and share it here; I'd then be glad to give you feedback on your work.</span>
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