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FinnZ [79.3K]
3 years ago
14

HELP ME PLEASE!

Mathematics
1 answer:
Delicious77 [7]3 years ago
7 0
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides).  If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.

Let's see whether they do.

8^2 + 8^2 = 11^2  ???
 64    + 64 = 121?  NO.  This is not a right triangle.

If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:

8^2 + 8^2 = d^2, where d=hypotenuse.  Then 64+64 = d^2, and 

d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.

11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
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kogti [31]

Answer:

James will end up with his original t cars and half of (t+13) cars, so will have ...

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Step-by-step explanation:

5 0
2 years ago
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Artist 52 [7]

Answer:

Hypotenuse = 14.1421 inches (rounded off to four decimal values)

Step-by-step explanation:

The legs of an isosceles triangle both measure 10 inches

Since the triangle is a right triangle,

We apply the Pythagorean Theorem to find the height of the hypotenuse

a² + b² = c²

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So; 10² + 10² = c²

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c = \sqrt{200} = 14.1421356237 inches

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3 years ago
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OlgaM077 [116]

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6 0
3 years ago
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What is the slope of a line that passes through -8, -16 and 18, 5?
ddd [48]
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_____
x2 - x1


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3 years ago
Help!! Only one attempt left!
Arturiano [62]

Answer:

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