Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
Answer: 50.27
Step-by-step explanation:
Area = pi r^2
= pi x 16
$20×.25=$5
$20-$5=$15
$15×.15=$2.25
$15+$2.25=$17.25
$17.25 is your answer
Write an equation to show all elements:
Cost of 4 lots of b (beads) + cost of 4p (pendants) = $18.80
Put values in;
9.29 + 4p = 18.80
4p = 18.80 - 9.20
4p = 9.60
p = 2.40 cost of each pendant
(2*length)+(2*width)=perimeter
length=4+2w
(2(4+2w))+(2(w))=74
74=(8+4w)+(2w)
74=6w+8
66=6w
w=11
length=4+2(11)
l=4+22
l=26
