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creativ13 [48]
2 years ago
6

PLEASE HELP ME WITH MY PROBLEM!!! 50 POINTS!!!

Mathematics
1 answer:
Molodets [167]2 years ago
5 0

Well he started off right by solving for y=y to find the abscissa of the intersection points between the two points,but then he assumed that their ordinate (y coordinates) are both zero,which is incorrect obviously. To find their ordinate,all we have to do is plug the x values into any of the two equations, since they both will pass through that point ੴ

y = 4 x+ 1 \\ y = 4(3) + 1  \\ y = 12 + 1 \\ y = 13

y = 4x + 1 \\ y = 4( - 2) + 1 \\ y =  - 8 + 1 \\ y =  - 7

I chose to plug the values in the second linear equation, since it's easier to compute

<h2>Points:</h2>

<h2>( 3 , 13 ) ( -2 , -7 )</h2>
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Write each equation in standard form using integers? <br><br> y = 3x + 1<br><br> y = 4x - 7
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Answer:

The standard form of y = 3 x + 1 is         -3x + y = 1 .

The standard form of y  = 4x - 7 is         -4x + y = -7.

Step-by-step explanation:

Here the given equation are:

y = 3 x + 1

and y  = 4x - 7

The above equations are of the form:  y = m x + C

Now, the STANDARD FORM of the equation is Ax + By  = C

<u>Consider equation 1: </u>

y = 3 x + 1

or, y - 3x  = 1

or. -3x + y = 1

⇒ The equation  -3x + y = 1  is in STANDARD FORM.

<u>Consider equation 2: </u>

y = 4 x - 7

or, y - 4x  = -7

or. -4x + y = -7

⇒ The equation -4x + y = -7 is in STANDARD FORM.

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3 years ago
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ss7ja [257]

Answer:

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Step-by-step explanation:

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