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Art [367]
3 years ago
5

Simplify the expression: 3^-3 a) -1/27 b) -27 c) 27 d) 1/27

Mathematics
1 answer:
uysha [10]3 years ago
7 0
The answer is b)-27 :)
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Many myths persist about how prior events affect the chances of future events.
Maru [420]
If it is a fair coin and if it is being flipped properly, previous events will NOT affect the 20th flip.

3 0
3 years ago
Last year a construction worker had a gross income $ 29,700, of the which he contributed 7% to his 401(k) plain. If he got paid
AlladinOne [14]

Divide the gross income by 12 to find his monthly pay:


29,700 / 12 =$2,475 per month.


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8 0
3 years ago
GETS BRAINLIEST AND 100 POINTS!!!!!<br> FIND THE INTERVAL OF THE CONVERGENCE
harina [27]

Answer:

Look at explanation

Step-by-step explanation:

Ok,

I got...

radius of convergence = 1

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8 0
3 years ago
Which of the following represents the most accurate estimation of 375 + 147?
GaryK [48]
Well, something around 522 so probably like 500 or 525
7 0
3 years ago
Let C = {n ∈ Z | n = 6r – 5 for some integer r} and D = {m ∈ Z | m = 3s + 1 for some integer s}.
noname [10]

Its is true that C ⊆ D means Every element of C is present in D

According to he question,

Let C = {n ∈ Z | n = 6r – 5 for some integer r}

D = {m ∈ Z | m = 3s + 1 for some integer s}

We have to prove : C ⊆ D

Proof : Let n ∈ C

Then there exists an integer r such that:

n = 6r - 5

Since -5 = -6 + 1

=> n = 6r - 6 + 1

Using distributive property,

=> n = 3(2r - 2) +1

Since , 2 and r are the integers , their product 2r is also an integer and the difference 2r - 2 is also an integer then

Let s = 2r - 2

Then, m = 3r + 1 with r some integer and thus m ∈ D

Since , every element of C is also an element of D

Hence ,  C ⊆ D proved !

Similarly, you have to prove D ⊆ C

To know more about integers here

brainly.com/question/15276410

#SPJ4

7 0
2 years ago
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