Answer:
∠ EML = 94°
Step-by-step explanation:
See the attached diagram.
The three angles ∠ NME, ∠ EML and ∠ NML together make 360°.
Now, ∠ NME = x + 97, ∠ EML = x + 66 and ∠ NML = 141°
Hence, (x + 97) + ( x + 66) + 141 = 360
⇒ 2x + 304 = 360
⇒ 2x = 56
⇒ x = 28
So, ∠ EML = x + 66 = 28 + 66 = 94° (Answer)
He would have to pay $560 because if you take 20% off of the computer using the equation 1000 - (1000 * 0.20) you get 800. This means that the 30% coupon is applied to $800, so using the same template as the equation above, we can do 800 - (800 * 0.30) to get a final answer of 560.
The correct answer would be B.6 and 7
X + y = 1.....multiply by -2
2x - 3y = -30
-----------------
-2x - 2y = -2 (result of multiplying by -2)
2x - 3y = -30
----------------add
-5y = -32
y = -32/-5
y = 32/5 or 6.4 <===
Answer:
The probability that the restaurant can accommodate all the customers who do show up is 0.3564.
Step-by-step explanation:
The information provided are:
- At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
- If the probability of a party not showing up is 0.04.
- Assuming independence.
Let <em>X</em> denote the number of parties that showed up.
The random variable X follows a Binomial distribution with parameters <em>n</em> = 53 and <em>p</em> = 0.96.
As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.
Compute the probability that the restaurant can accommodate all the customers who do show up as follows:
![P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564](https://tex.z-dn.net/?f=P%28X%5Cleq%2050%29%3D1-P%28X%3E50%29%5C%5C%3D1-P%28X%3D51%29-P%28X%3D52%29-P%28X%3D53%29%5C%5C%3D1-%5B%7B53%5Cchoose%2051%7D%280.96%29%5E%7B51%7D%280.04%29%5E%7B53-51%7D%5D-%5B%7B53%5Cchoose%2052%7D%280.96%29%5E%7B52%7D%280.04%29%5E%7B53-52%7D%5D%5C%5C-%5B%7B53%5Cchoose%2053%7D%280.96%29%5E%7B53%7D%280.04%29%5E%7B53-53%7D%5D%5C%5C%3D1-0.27492-0.25377-0.11491%5C%5C%3D0.3564)
Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.