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2 years ago

What is an equation of the line that passes through the points (0,7) and (5,4? Put your answer in fully reduced form.

Mathematics

1 answer:

gregori [183]2 years ago

4 0

Answer <u>(assuming it can be in slope-intercept format)</u>:

$y = -\frac{3}{5} x+7$

Step-by-step explanation:

When knowing the y-intercept of a line and its slope, we can write an equation representing it in slope-intercept form, or $y = mx + b$ .

1) First, find the slope of the equation. Use the slope formula, $m = \frac{y_2-y_1}{x_2-x_1}$ , to find the slope. Substitute the x and y values of the given points into the formula and simplify:

$m = \frac{(4)-(7)}{(5)-(0)} \\m = \frac{4-7}{5-0} \\m = \frac{-3}{5}$

Thus, the slope is $-\frac{3}{5}$ .

2) Usually, we would have to use one of the given points and the slope to put the equation in point-slope form. However, notice that the point (0,7) has an x-value of 0. All points on the y-axis have an x-value of 0, thus (0,7) must be the y-intercept of the line. Now that we know the slope of the line and its y-intercept, we can already write the equation in slope-intercept format, represented by the equation $y = mx + b$ . Substitute $m$ and $b$ for real values.

Since $m$ represents the slope, substitute $-\frac{3}{5}$ in its place in the equation. Since $b$ represents the y-intercept, substitute 7 in its place. This gives the following equation and answer:

$y = -\frac{3}{5} x+7$

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Answer:

Supplementary, 39+5x=180, x=28.2

Step-by-step explanation:

So we know that a straight line is 180 degrees, therefore 52+(5x-13) must equal 180. This is a supplementary relationship. That's our equation, now we just have to solve.

52+5x-13=180

We can straight away combine numbers, giving us

39+5x=180

Now we subtract 39 from both sides, giving us

5x=141.

Now we will answer.

141/5=28.2=x

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Alex787 [66]

There are 5 groups of 3 in the number 15, so 15/3=5

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Given the expression, 3(y + 1) + 2y, which of the following expressions is equivalent?

Vera_Pavlovna [14]

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5y +3

Step-by-step explanation:

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What is the equation of the line that passes through the point (-6,1) and has a slope of 1/6

anyanavicka [17]

Answer:y=1/6x+2

Step-by-step explanation:

Y=1/6x+b

Plug in (-6,1)

1=1/6(-6)+b

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2 years ago

Use Gaussian elimination to write each system in triangular form

Feliz [49]

Answer:

To see the steps to the diagonal form see the step-by-step explanation. The solution to the system is $x = -\frac{1}{9}$ , $y= -\frac{1}{9}$ , $z= \frac{4}{9}$ and $w = \frac{7}{9}$

Step-by-step explanation:

Gauss elimination method consists in reducing the matrix to a upper triangular one by using three different types of row operations (this is why the method is also called row reduction method). The three elementary row operations are:

Swapping two rows
Multiplying a row by a nonzero number
Adding a multiple of one row to another row

To solve the system using the Gauss elimination method we need to write the augmented matrix of the system. For the given system, this matrix is:

$\left[\begin{array}{cccc|c}1 & 1 & 1 & 1 & 1 \\1 & 1 & 0 & -1 & -1 \\-1 & 1 & 1 & 2 & 2 \\1 & 2 & -1 & 1 & 0\end{array}\right]$

For this matrix we need to perform the following row operations:

$R_2 - 1 R_1 \rightarrow R_2$ (multiply 1 row by 1 and subtract it from 2 row)
$R_3 + 1 R_1 \rightarrow R_3$ (multiply 1 row by 1 and add it to 3 row)
$R_4 - 1 R_1 \rightarrow R_4$ (multiply 1 row by 1 and subtract it from 4 row)

$R_2 \leftrightarrow R_3$ (interchange the 2 and 3 rows)

$R_2 / 2 \rightarrow R_2$ (divide the 2 row by 2)
$R_1 - 1 R_2 \rightarrow R_1$ (multiply 2 row by 1 and subtract it from 1 row)
$R_4 - 1 R_2 \rightarrow R_4$ (multiply 2 row by 1 and subtract it from 4 row)
$R_3 \cdot ( -1) \rightarrow R_3$ (multiply the 3 row by -1)
$R_2 - 1 R_3 \rightarrow R_2$ (multiply 3 row by 1 and subtract it from 2 row)
$R_4 + 3 R_3 \rightarrow R_4$ (multiply 3 row by 3 and add it to 4 row)
$R_4 / 4.5 \rightarrow R_4$ (divide the 4 row by 4.5)

After this step, the system has an upper triangular form

The triangular matrix looks like:

$\left[\begin{array}{cccc|c}1 & 0 & 0 & -0.5 & -0.5 \\0 & 1 & 0 & -0.5 & -0.5\\0 & 0 & 1 & 2 & 2 \\0 & 0 & 0 & 1 & \frac{7}{9}\end{array}\right]$

If you later perform the following operations you can find the solution to the system.

$R_1 + 0.5 R_4 \rightarrow R_1$ (multiply 4 row by 0.5 and add it to 1 row)
$R_2 + 0.5 R_4 \rightarrow R_2$ (multiply 4 row by 0.5 and add it to 2 row)
$R_3 - 2 R_4 \rightarrow R_3$ (multiply 4 row by 2 and subtract it from 3 row)

After this operations, the matrix should look like:

$\left[\begin{array}{cccc|c}1 & 0 & 0 & 0 & -\frac{1}{9} \\0 & 1 & 0 & 0 & -\frac{1}{9}\\0 & 0 & 1 & 0 & \frac{4}{9} \\0 & 0 & 0 & 1 & \frac{7}{9}\end{array}\right]$

Thus, the solution is:

$x = -\frac{1}{9}$ , $y= -\frac{1}{9}$ , $z= \frac{4}{9}$ and $w = \frac{7}{9}$

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2 years ago