Answer:
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Step-by-step explanation:
Given data
mean = 5.1 millimeters (mm)
standard deviation = 0.7 mm
to find out
percent (%) of ancient prehistoric thinner than 3
solution
we have given mean and SD
so Z will be = x -mean / SD
Z = ( x - 5.1 ) / 0.7
so P( x < 3 ) = P ( (x - 5.1 ) / 0.7 < ( 3 - 5.1 ) / 0.7 )
P( Z = ( 3 - 5.1 ) / 1.5 )
P( Z = -3 ) = 0.0013
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Step-by-step explanation:
3(12)=2(y-1)
36=2y-2
36+2=2y
38=2y(<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>two</em><em>)</em>
y=19
(1 yard )3<span> = 1</span>3<span> yard*yard*yard</span><span> = 1 yard*yard*yard</span><span> = 1 cubic yard . Since 1 yard = </span>3 feet, we have.
1 cubic yard = (1 yard)3<span> = (</span>3 feet)3<span> = </span><span>33 feet*feet*feet</span><span> = </span>27 cubic feet<span>.</span>
From angle bisector theorem, we know that:
Moreover:
so:
and
