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Nezavi [6.7K]
2 years ago
9

Shanice's school made $850 by selling 125 tickets to the annual talent show. They sold adult

Mathematics
2 answers:
8090 [49]2 years ago
6 0
Let S = student
Let A = adult
First equation is total tickets
Second should be the cost
S + A = 125
6S + 10A = 850
Use substitution or elimination
S + A = 125
S = -A + 125
I used substitution
6(-A + 125) + 10A = 850
-6A + 750 + 10A = 850
4A + 750 = 850
4A = 100, A = 25 adult tickets
125 - 25 = 100

Solution: 100 student tickets
Romashka-Z-Leto [24]2 years ago
3 0

Answer:

25 adult tickets were sold and 100 student tickets were sold.

Step-by-step explanation:

Let the number of adult tickets sold be x and the number of student tickets sold be y.

We know that the total amount collected from the tickets was $850, and that a total of 125 tickets were sold. We can use this information to come up with two equations.

10x + 6y = 850 - Equation 1

x + y = 125 - Equation 2

Then, use the substitution method to solve for either x or y first, followed by the other.

From equation two:

x + y = 125

x = 125 - y - Equation 3

Sub eqn 3 into eqn 1:

10(125-y) + 6y = 850

1250 - 10y + 6y = 850

1250 - 4y = 850

-4y = - 400

y - 100

Sub y = 100 into eqn 2:

x + 100 = 125

x = 25

Check:

10(25) + 6(100) = 850

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Realiza estas operaciones y expresa el resultado en metros 1m-(5dm3cm) (2hm4m)+35dam (3hm6dam)+(8dam5m) (2m5dm6cm)-85cm
ivolga24 [154]

Answer:

126.109,63 m

Step-by-step explanation:

Por conveniencia, todas las unidades se convierten a m

1000 m = 1 km

100 m = 1hm

10m = 1 presa

1 m = 1 m

10dm = 1m

100 cm = 1 m

1000 mm = 1 m

1m- (5dm3cm) (2hm4m) + 35dam (3hm6dam) + (8dam5m) (2m5dm6cm) -85cm

= 1m- (5/10 +3/100) (2 * 100 + 4m) + 35 * 10 (3 * 100 + 6 * 10) + (8 * 10 + 5m) (2m + 5/10 + 6/100 ) -85/100

= 1 m- (0.5 +0.03) (200 + 4m) +350 (300 +60) + (80 + 5m) (2m + 0.5 + 0.06) -85/100

= 1 m- (0,53) (204 m) +350 (360) + (85 m) (2,56) -85/100

= 1 m- (108,12 m) +126000+ (217,6) - 0,85

= 126.109,63 m

For convenience all units are converted to m

1000m = 1km

100 m= 1hm

10m = 1 dam

1m= 1m

10dm= 1m

100 cm= 1 m

1000 mm= 1m

1m-(5dm3cm) (2hm4m)+35dam (3hm6dam)+(8dam5m) (2m5dm6cm)-85cm

= 1m-(5/10 +3/100) (2*100 +4m)+35*10 (3*100 +6*10)+(8*10+5m) (2m+5/10+6/100)-85/100

= 1m-(0.5 +0.03) (200 +4m)+350 (300 +60)+(80+5m) (2m+0.5+0.06)-85/100

= 1m-(0.53) (204m)+350 (360)+(85m) (2.56)-85/100

= 1m-(108.12m)+126000+(217.6)- 0.85

= 126,109.63 m

5 0
3 years ago
Find the least common multiple of x2 – 4x – 5 and x2 – 3x – 10.
vfiekz [6]

<u>x² - 4x - 5</u>                           <u>x² - 3x - 10</u>

(x - 5)(x + 1)                         (x - 5)(x + 2)

                  GCF: (x - 5)

                  LCM: (x - 5)(x + 1)(x + 2)

Answer: (x - 5)(x + 1)(x + 2)

5 0
3 years ago
Antwan determines the distance between the points –7 and 2 on a numberline. Maggie determines the difference between the numbers
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Answer:

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Step-by-step explanation:

5 0
3 years ago
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Answer:

A

Step-by-step explanation:

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5 0
3 years ago
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Shalnov [3]

Answer:

By the Empirical Rule, 68% of IQ scores are between 87 and 121

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

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So 121 is one standard deviation above the mean

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3 years ago
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