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2 years ago

Shanice's school made $850 by selling 125 tickets to the annual talent show. They sold adult

2 answers:

6 0

Let S = student
Let A = adult
First equation is total tickets
Second should be the cost
S + A = 125
6S + 10A = 850
Use substitution or elimination
S + A = 125
S = -A + 125
I used substitution
6(-A + 125) + 10A = 850
-6A + 750 + 10A = 850
4A + 750 = 850
4A = 100, A = 25 adult tickets
125 - 25 = 100

Solution: 100 student tickets

Romashka-Z-Leto [24]2 years ago

3 0

Answer:

25 adult tickets were sold and 100 student tickets were sold.

Step-by-step explanation:

Let the number of adult tickets sold be x and the number of student tickets sold be y.

We know that the total amount collected from the tickets was $850, and that a total of 125 tickets were sold. We can use this information to come up with two equations.

10x + 6y = 850 - Equation 1

x + y = 125 - Equation 2

Then, use the substitution method to solve for either x or y first, followed by the other.

From equation two:

x + y = 125

x = 125 - y - Equation 3

Sub eqn 3 into eqn 1:

10(125-y) + 6y = 850

1250 - 10y + 6y = 850

1250 - 4y = 850

-4y = - 400

y - 100

Sub y = 100 into eqn 2:

x + 100 = 125

x = 25

Check:

10(25) + 6(100) = 850

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Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa

4vir4ik [10]

Using the z-distribution, it is found that since the test statistic is greater than the critical value, it can be concluded that the mean length of jail time has increased.

At the null hypothesis, it is tested if the mean length of jail time is still of 2.5 years, that is:

$H_0: \mu = 2.5$

At the alternative hypothesis, it is tested if it has increased, that is:

$H_1: \mu > 2.5$

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the sample.
n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 3, \mu = 2.5, \sigma = 1.5, n = 26$

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{3 - 2.5}{\frac{1.5}{\sqrt{26}}}$

$z = 1.7$

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05, is of $z^{\ast} = 1.645$

Since the test statistic is greater than the critical value, it can be concluded that the mean length of jail time has increased.

A similar problem is given at brainly.com/question/24166849

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2 years ago

Two dice are numbered 1,2,3,4,5,6 and 1,1,2,2,3,3 respectively. They are rolled and

Alexxx [7]

Answer:

P(2) = 1/18

P(3) = 1/9

P(4) = 1/6

P(5) = 1/6

P(6) = 1/6

P(7) = 1/6

P(8) = 1/9

P(9) = 1/18

Step-by-step explanation:

Each die has six possible outcomes, so both dice together have 6*6 = 36 outcomes:

(1,1), (1,1), (1,2), (1,2), (1,3), (1,3),

(2,1), (2,1), (2,2), (2,2), (2,3), (2,3),

(3,1), (3,1), (3,2), (3,2), (3,3), (3,3),

(4,1), (4,1), (4,2), (4,2), (4,3), (4,3),

(5,1), (5,1), (5,2), (5,2), (5,3), (5,3),

(6,1), (6,1), (6,2), (6,2), (6,3), (6,3).

The sum of the values for each outcome is:

2, 2, 3, 3, 4, 4,

3, 3, 4, 4, 5, 5,

4, 4, 5, 5, 6, 6,

5, 5, 6, 6, 7, 7,

6, 6, 7, 7, 8, 8,

7, 7, 8, 8, 9, 9.

To find the probability of each sum, we just need to divide the number of times this sum appears over the total number of possibilities (36), so we have:

P(2) = 2/36 = 1/18

P(3) = 4/36 = 1/9

P(4) = 6/36 = 1/6

P(5) = 6/36 = 1/6

P(6) = 6/36 = 1/6

P(7) = 6/36 = 1/6

P(8) = 4/36 = 1/9

P(9) = 2/36 = 1/18

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3 years ago

Rentite in simplest terms: - 10(9c – 7c+8) - 80

zhannawk [14.2K]

Answer:

-20c-160

Step-by-step explanation:

-10(9c-7c+8)-80

-10(2c+8)-80

-20c-80-80

-20c-160

8 0

3 years ago

Read 2 more answers

Quadrilateral LMNO is a parallelogram, and LM=24-9 and NO=y-2, find the value of "y" and the length of NO.

Slav-nsk [51]

Answer:

y = 7

NO = 5

Step-by-step explanation:

Let the side of the parallelogram LM and NO given be 2y - 9 and y - 2

Since LMNO is a parallelogram, hence;

LM = NO

2y - 9 = y - 2

2y - y = -2 + 9

y = 7

Since NO = y - 2

NO = 7 - 2

NO = 5

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2 years ago

Two cards are drawn from a standard deck without replacement. What is the probability that the first card is a spade and the sec

Verizon [17]

Answer:

The answer is 0.123.

Step-by-step explanation:

You want to find the intersection between P(Spade) and P(Red). Knowing that there's no replacement, the probability will be given by the formula:

⇒ P(Spade∩Red) = P(Spade)*P(Red/Spade)

⇒ P(Spade∩Red) = P(Red)*P(Spade/Red)

Either formula works, but I'm going to choose to work with the first formula.

Therefore:

P(Spade) = $\frac{13}{52}$

P(Red/Spade) = $\frac{26}{52-1}$

So:

P(Spade∩Red) = $\frac{13}{52}$ * $\frac{26}{51}$ = $\frac{13}{102}$ = $0.123$

3 0

3 years ago