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gtnhenbr [62]
3 years ago
9

Assume that two marbles are drawn without replacement from a box with 1 blue, 3 white, 2 green, and 2 red marbles. find the prob

ability of the indicated result. 20) both marbles are red.
Mathematics
1 answer:
Leona [35]3 years ago
8 0
The first time I believe it's 1/4 and then 1/7
You might be interested in
Vonda works between 30 and 32 hours per week at a hair salon. She pays a one time $250 chair rental fee, and earns $40 per hour
Vlad1618 [11]

Answer:

The practical domain of the function is [30,32].

Step-by-step explanation:

The given function is

p(h)=40h-250

where, p(h) represents the Vonda's weekly pay as a function of hours worked.

She pays a one time $250 chair rental fee, and earns $40 per hour that she works.

Domain is the set of all possible inputs.

The possible domain of the given function is all real numbers but the number of hours can not be negative, therefore  h>0.

It is given that Vonda works between 30 and 32 hours per week at a hair salon. So,

30

Therefore practical domain of the function is [30,32].

3 0
3 years ago
What is the value of the function at x = 3?
BARSIC [14]
The value is 3 because x=3 right there! it's not even a question, just an answer!
6 0
3 years ago
What is the correct justification for the indicated steps?
yanalaym [24]

The given proof of De Moivre's theorem is related to the operations of

complex numbers.

<h3>The Correct Responses;</h3>
  • Step A: Laws of indices
  • Step C: Expanding and collecting like terms
  • Step D: Trigonometric formula for the cosine and sine of the sum of two numbers

<h3>Reasons that make the above selection correct;</h3>

The given proof is presented as follows;

\mathbf{\left[cos(\theta) + i \cdot sin(\theta) \right]^{k + 1}}

  • Step A: By laws of indices, we have;

\left[cos(\theta) + i \cdot sin(\theta) \right]^{k + 1} = \mathbf{\left[cos(\theta) + i \cdot sin(\theta) \right]^{k} \cdot \left[cos(\theta) + i \cdot sin(\theta) \right]}

\left[cos(\theta) + i \cdot sin(\theta) \right]^{k} \cdot \left[cos(\theta) + i \cdot sin(\theta) \right] =  \mathbf{\left[cos(k \cdot \theta) + i \cdot sin(k \cdot \theta) \right] \cdot \left[cos(\theta) + i \cdot sin(\theta) \right]}

  • Step B: By expanding, we have;

\left[cos(k \cdot \theta) + i \cdot sin(k \cdot \theta) \right] \cdot \left[cos(\theta) + i \cdot sin(\theta) \right] = cos(k \cdot \theta) \cdot cos(\theta) - sin(k \cdot \theta) \cdot sin(\theta) + i  \cdot \left [sin(k \cdot \theta) \cdot cos(\theta) + cos(k \cdot \theta) \cdot sin(\theta) \right]

  • Step D: From trigonometric addition formula, we have;

cos(A + B) = cos(A)·cos(B) - sin(A)·sin(B)

sin(A + B) = sin(A)·cos(B) + sin(B)·cos(A)

Therefore;

cos(k \cdot \theta) \cdot cos(\theta) - sin(k \cdot \theta) \cdot sin(\theta) + i  \cdot \left [sin(k \cdot \theta) \cdot cos(\theta) + cos(k \cdot \theta) \cdot sin(\theta) \right] = \mathbf{ cos(k \cdot \theta + \theta) + i \cdot sin(k \cdot \theta  + \theta)}

Learn more about  complex numbers here:

brainly.com/question/11000934

4 0
2 years ago
Read 2 more answers
Pleaseeee help I already have the graph.
vekshin1

Answer: 5x + 2y = 8 = x=-2/5y+8/5

y = 3x - 7= x= 1/3y+7/3

Step-by-step explanation:

7 0
3 years ago
Find and fix the incorrect statement
Svetlanka [38]
Statement #3 is incorrect. The actual ratio is 1/15. The rest of the statements are true.
4 0
2 years ago
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