Answer:
Eli has to run for 2.25 minutes at this pace to win the bet.
Step-by-step explanation:
At his last track meet, Eli ran the 400-meter dash in 54 seconds.
So, the speed of Eli's run is
meters per minute.
Now, if Eli is determined to run a whole kilometer with the same speed, then it will take Eli to run 1 kilometer within
minutes.
Hence, Eli has to run for 2.25 minutes at this pace to win the bet. (Answer)
The value of the expression is 3.5 × 10³.
<h3>How to calculate the expression?</h3>
It should be noted that the expression given is 5 times 10 squared end quantity times quantity 4.2 times 10 to the fourth power end quantity all divided by quantity 6 times 10 cubed.
This will be:
5 × 10² × 4.2 × 10⁴ / 6 × 10³
= 3.5 × 10³
The value of the expression is 3.5 × 10³.
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Answer:
2 cows and 5 chickens.
Step-by-step explanation:
NOTE: This will be solved using simultaneous equations.
Let x = cows and y = chickens
1. form two equations
4x + 2y = 18 ... (1)
x + y = 7 .... (2)
2. make y (or x) the subject of one equation
x + y = 7
y = 7 - x ... (3)
3. Substitute (3) into (1)
4x + 2( 7 - x) = 18
4. solve for x
4x + 14 - 2x = 18
2x = 4
x = 2
5. Now substitute x value into equation (2)
x + y = 7
2 + y = 7
y = 5
∴ cows (x) = 2
chickens (y) = 5
Answer:4n+12
Step-by-step explanation:
Answer:
17.5%
Step-by-step explanation:
First of all, see this situation as a cumulative binomial distribution. You have isolated trials with a probability of success. This makes it binomial. The wording of the question "what is the probability of at least half..." makes this cumulative.
There are a few ways to calculate this, and I'm not quite sure which way you're familiar with. I'll show the cumbersome way and use wolfram to make the calculation.
First, I'll calculate the probability for 15 success, given 30 trials.
30c15*0.4^15*0.6^15
Since the question asks for the probability of at least 15 success, I'll have to make a calculation for the probability of 16 successes, then 17, and so on. Then I'll have to add all the probabilities together. So, I'll use wolfram for that (see attached)