Ask question

Ask question

All categories

3 years ago

13

At the amusement park, Laura paid $6.00 for small cotton candy. Her older brother works at the park, and he told her they mark u

p the cotton candy by 300%. What is the price of the cotton candy before the markup?

2 answers:

LuckyWell [14K]3 years ago

8 0

I think it’s $2 dollars sorry if I’m wrong

Rudiy273 years ago

3 0

$2 because 6/%300= 2

You might be interested in

Can anyone solve this no links

lesantik [10]

The answer would be x=103 degrees

6 0

3 years ago

What is the solution coordinates to the graphed system of equations?

VARVARA [1.3K]

Answer:

We conclude that the solution coordinates to the graphed system of equations will be:

(x, y) = (1, -5)

Step-by-step explanation:

From the given graph it is clear that there are two lines:

Red and Blue

It is clear that the red and blue lines meet or intersect at the point (1, -5). The point where the two lines meet is called the point of intersection.

In other words, the two lines meet at:

at x = 1, and y = -5

Thus, the point of intersection of two lines is:

(x, y) = (1, -5)

We also know that the point of intersection of two lines is the solution of the system of equations.

Therefore, we conclude that the solution coordinates to the graphed system of equations will be:

(x, y) = (1, -5)

4 0

3 years ago

Deisha can build a fence in 15 hours, and Travis can build a fence in 12 hours. How long will it take them together to build a f

Basile [38]

Answer:

6 $\frac{2}{3}$

Step-by-step explanation:

Deisha's build rate = 1 fence per 15 hours = 1/15 fences per hour

Travis's build rate = 1 fence per 12 hours = 1/12 fences per hour

Working together, their combined rate is 1/15 + 1/12 = 3/20 fences per hour

So it takes them 20/3 = 6 2/3 hours per fence

6 0

3 years ago

(4 + y = 19) what is y

Fiesta28 [93]

4 + y = 19

y = 19 - 4

y = 15

5 0

3 years ago

Find the area of an acute triangle with a base of 13 inches and a height of 5 inches.

MArishka [77]

Base=B=13in
Height=H=5in

Area:-

$\\ \rm\hookrightarrow \dfrac{1}{2}BH$

$\\ \rm\hookrightarrow \dfrac{1}{2}(13)(5)$

$\\ \rm\hookrightarrow 65/2$

$\\ \rm\hookrightarrow 32.5in^2$

6 0

3 years ago