To get the mean distance that Jim jogged, you have to solve
for the total miles he was able to jogged divided by the number of days he
jogged.
6.5 miles + 5 miles + 3 miles + 2 miles + 3.5 miles + 4
miles = 24 miles / 6 days = 4
Therefore, the mean distance that Jim jogged is 4 miles.
-6x^4y^5-15x^3y^2+9x^2y^3
The GCF OF -6, -15, & 9, is -3
The GCF OF x's is x^2
The GCF OF y's is y^2
These are the number of x's and y's that each term has.
-3x^2y^2(2x^2y^3+5x-3y)
LETTER B
Just divide. 3/4 is 3 divided by 4= .75
75 hundredths is the same as 75%
20/100 20 divided by 100=.20 which is 20%
14 divided by 25 is .56, or 56%
1/5 is 1 divided by 5 = .20 or 20 %
I believe the correct answer from the choices listed above is option A. The <span>system can be changed so that the two equations have equal x-coefficients by multiplying </span><span>both sides of the top equation by 2 resulting to 6x + 4y = 24. Hope this answers the question.</span>
