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horrorfan [7]
3 years ago
8

The variables x and y are related proportionally. When x = 8, y = 20. Find y when x = 42.

Mathematics
1 answer:
Mkey [24]3 years ago
7 0

Answer:

y = 2.5(42)

Step-by-step explanation:

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April lost 5 pounds in her first week of college. Over the next three weeks she lost 3 pounds, gained 2 pounds, and then lost 1
Doss [256]

Change in April's weight is -7

<em><u>Solution:</u></em>

Let the initial weight be "x"

April lost 5 pounds in her first week of college

First week = lost 5 pounds

Therefore, x - 5

Over the next three weeks she lost 3 pounds, gained 2 pounds, and then lost 1 pound

<em><u>Next three week:</u></em>

Lost 3 pound

Gained 2 pound

Lost 1 pound

<em><u>Therefore, weight after 4 weeks is given as:</u></em>

x - 5 - 3 + 2 - 1 = x -7

After 4 week, the weight is x - 7

<em><u>The change in April weight is given as:</u></em>

Weight after 4 week - initial weight = x - 7 - x = -7

Thus change in April's weight is -7 (Negative sign represents loss in weight )

4 0
3 years ago
Solve for B in the picture below
Oxana [17]

Answer:

b= -48

Step-by-step explanation:

by transposing,

43=59+b/3

b/3+59=43

b/3=43-59

b/3= -16

b= -16×3

b= -48

therefore the answer is b= -48

hope it helps!!!

PLEASE MARK BRAINLIEST..

5 0
2 years ago
Read 2 more answers
Algebra 2 please help
damaskus [11]
I believe this is correct:
13 x^3-78x^2-234x

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8 0
3 years ago
Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min
leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

                                \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2}.

First, we simplify the expression in the numerator of the fraction.

3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72

Now, we obtain

                         12(x^2-x-6) = 12(x+2)(x-3)

and the fraction is transformed into

                       \frac{3(2x-1)^2 - 75}{x+2} =  \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)

Therefore, the following limit is

       \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2}  12(x-3) = 12 \lim_{x \to -2} (x-3)

You can plug in -2 in the equation, hence

                        12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60

6 0
3 years ago
A tree that is 100 feet tall casts a shadow that is 150 feet long. Determine the angle at which the rays of the sun hit the grou
Dvinal [7]

Answer:

Step-by-step explanation:

A tree that is 100 feet tall casts a shadow that is 150 feet long ...

The angle at which the ray of the sun hit the ground is that which has a tangent equal to 100 / 150 or 2/3. This angle is equal to 33.69. Thus, the answer is letter B. 34°

5 0
3 years ago
Read 2 more answers
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