To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
Answer:
0.42* 1265=x
Step-by-step explanation:
There are 1265 students in Cypress Middle School. So we already know one part of the equation. 42% of these students are in PE. So we know that 42% of these 1265 students are in PE. Of these means you probably have to multiply 42% and 1265. 42% = 0.42. So to write an equation we take the 0.42 and 1265 and put it together. Therefore, 0.42 times 1265=x.
The equation, when rewritten would be written as:
q = ( c - 54293 ) / 3.59
<h3>How to rewrite the equation in order to make q the subject</h3>
C = 3.59q + 54,293
We have the equation above, what we would have to do now would be to write the equation in such a way that q would be the subject of the formula.
This would be
3.59q = C - 54,293
Next we have to divide through by the value of q
q = 
Read more on subject of formula here: brainly.com/question/21140562
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We know that the point is in Q II. Thus, the x-coordinate of this point will be negative and the y-coordinate will be positive.
The y-coordinate is essentially given, and is y=4.
Imagine drawing a vertical line thru x=-2. This line will intersect y=4 at (-2,4).
The coordinates of the point are (-2, -4).
