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2 years ago

Solve for x. 3(x−7)=6(x−10) Enter your answer in the box. x =

Mathematics

1 answer:

Oksi-84 [34.3K]2 years ago

4 0

Answer:

X = 13

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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3 years ago

San Antonio, Texas, is located about 30° north of the equator. If Earth's radius is about 3959 miles, approximately how many mil

marusya05 [52]

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2 years ago

(5x^2-4X + 7) - (4x + 2)

DanielleElmas [232]

5x’2-4x+7-4x-2
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5x’2-8x+7-2
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The answer is
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2 years ago

Which of the following would NOT be

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2 years ago

What is the simplified form of the following expression? Assume y=0 ^3 sqrt 12x^2/16y

pochemuha

For this case we must simplify the following expression:

$\sqrt [3] {\frac {12x ^ 2} {16y}}$

We rewrite the expression as:

$\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\frac{\sqrt[3]{3x^2}}{\sqrt[3]{4y}}=$

We multiply the numerator and denominator by:

$(\sqrt[3]{4y})^2:\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{\sqrt[3]{4y}*(\sqrt[3]{4y})^2}=$

We use the rule of power $a ^ n * a ^ m = a ^ {n + m}$ in the denominator:

$\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{(\sqrt[3]{4y})^3}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{4y}=$

Move the exponent within the radical:

$\frac{\sqrt[3]{3x^2}*(\sqrt[3]{16y^2}}{4y}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{2^3*(2y^2)}}{4y}=$

$\frac{2\sqrt[3]{3x^2}*(\sqrt[3]{(2y^2)}}{4y}=\\\frac{2\sqrt[3]{6x^2*y^2}}{4y}=$

$\frac{\sqrt[3]{6x^2*y^2}}{2y}$

Answer:

$\frac{\sqrt[3]{6x^2*y^2}}{2y}$

7 0

3 years ago

Read 2 more answers