All categories

2 years ago

Please help mee best answer will get brainliest.

Mathematics

2 answers:

Serga [27]2 years ago

6 0

Answer:

5x+1

Step-by-step explanation:

the perimeter is the outside values of the shape, and we know all the values, so we just have to add them all up.

(x+4) + (2x-1) + (3x-2) = perimeter

since it's all subtraction and addition we can remove the parentheses

x+4+2x-1+3x-2 = perimeter

now let's put all the x's on one side and the numbers on the other side to make it easier

x+2x+3x+4-1-2= perimeter

5x+1

Lapatulllka [165]2 years ago

5 0

Answer:

Perimeter of the triangle is :---

$(x + 4) + (3x - 2) + (2x + 1) \\ = x + 4 + 3x - 2 + 2x + 1 \\ = \boxed{(6x + 3 )\: ft }$

<h3>(6x+3) ft is the right answer.</h3>

You might be interested in

What is the incorrect rounding for 53.864

Alex17521 [72]

If you round the 6. Or if they ask u to round the tenth place or ones place and do the opposite or something else

6 0

3 years ago

I need help? can anyone help

erica [24]

I think it’s 5 but don’t get mad if it’s wrong

7 0

3 years ago

SOMEONE HELP IM LITTRALY GONNA CRY MY DUDES PLEASE

forsale [732]

Answer:

Step-by-step explanation:

ewqrui

6 0

3 years ago

Find the collame of boid of dimension 16cm X 10m x 6cm.

swat32

Question: Find the volume of cuboid of dimension 16cm X 10cm x 6cm.

Answer: Given Length=16cm, Breadth=10cm, Height=6cm

Using Volume formula for cuboid:-

$volume = l \times b \times h$

$→16 \times 10 \times 6$

$→960 \: cm^{3}$

So, volume of cuboid is 960 cm³

7 0

2 years ago

25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of

sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

$P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028$

b) Probability that exactly 2 has only cats (p=0.15)

$P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759$

c) Probability that exactly 1 has cats and dogs (p=0.1)

$P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742$

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

$P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508$

8 0

3 years ago