Question

Hello, how to do 12(c) ?:)

Answer 1

Step-by-step explanation:

27^x / sqrt(9^y) = 3 and log2(x) - 2 = log2(y).

3^3x / 3^y = 3 and log2(x) - log2(4) = log2(y).

3x - y = 1 and x/4 = y.

Therefore x = 4/11 and y = 1/11.

Answer 2

Answer:

( $\frac{4}{11}$ , $\frac{1}{11}$ )

Step-by-step explanation:

27 = 3³ and √9 = 3 and xy ≠ 0

$\frac{3^{3x} }{3^{y} }$ = 3 ⇔ $3^{3x-y}$ = $3^{1}$ ⇒ 3x - y = 1

$log_{2} x$ - 2 = $log_{2} y$ ⇔ $log_{2} x$ - $log_{2} y$ = 2 ⇔ $log_{2} \frac{x}{y}$ = 2 ⇒ $\frac{x}{y}$ = 2² ⇒ x = 4y

$\left \{ {{3x-y=1} \atop {x=4y}} \right.$

3(4y) - y = 1 ⇒ y = $\frac{1}{11}$ and x = $\frac{4}{11}$

( $\frac{4}{11}$ , $\frac{1}{11}$ )