Solution :
Demand for cola : 100 – 34x + 5y
Demand for cola : 50 + 3x – 16y
Therefore, total revenue :
x(100 – 34x + 5y) + y(50 + 3x – 16y)
R(x,y) = 

In order to maximize the revenue, set



.............(i)


.............(ii)
Solving (i) and (ii),
4 x (i) ⇒ 272x - 32y = 400
(ii) ⇒ (-<u>) 8x - 32y = -50 </u>
264x = 450
∴ 

So, x ≈ $ 1.70 and y = $ 1.99
R(1.70, 1.99) = $ 134.94
Thus, 1.70 dollars per cola
1.99 dollars per iced ted to maximize the revenue.
Maximum revenue = $ 134.94
Three hundred and six thousandths :)
Simplify the Value of:
6x + 1 The equation is already simplified, There are no like terms.
You cannot factor 6x + 1 either
Domain of:
6x + 1
Solution: [ - ∞ < x < ∞ ]
Interval Notation: [ (- ∞, ∞) ]
Range of:
6x + 1
Solution: [ - ∞ < f(x) < ∞ ]
Interval Notation: [ (- ∞, ∞) ]
Parity of:
6x + 1 =====> Neither even nor odd
Axis interception points of:
6x + 1
x- Intercepts ( - 1 / 6, 0 )
y- Intercepts ( 0, 1 )
Inverse of:
6x + 1 =====> x - 1 / 6
Slope of:
6x + 1
Answer: ======> m = 6
Hope that helps!!!!!!!!!! : )
The problem is cut off but the information i do have i think it is D